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3 years ago

15

Does anyone know how to answer this question? Please write your working calculation as well if you do know the answer. Thanks so

much.

1 answer:

krek1111 [17]3 years ago

5 0

Answer:

Mark as brainliest if helped Thanks!

Step-by-step explanation:

funtion is:

$y = \frac{x^2 -1}{2x + 1}$

therefore $\\\frac{dy}{dx}\\$ is

$\frac{d\frac{x^2 -1}{2x + 1}}{dx}$

$\frac{\frac{x^2 -1}{2x + 1}}{x}$

$\frac{x^2 -1}{(2x+1) x}$

Now

$\int\limits^2_0 {\frac{x^2 +x +1 }{4x^2 +4 + 1} } \, dx$

(Calculation of this it too long and it is hard to type on brainly)

here is the answer though....

= 4/5

=0.8

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