Question

Does anyone know how to answer this question? Please write your working calculation as well if you do know the answer. Thanks so much. ​

Answer 1

Answer:

Mark as brainliest if helped Thanks!

Step-by-step explanation:

funtion is:

$y = \frac{x^2 -1}{2x + 1}$

therefore $\\\frac{dy}{dx}$ is

$\frac{d\frac{x^2 -1}{2x + 1}}{dx}$

$\frac{\frac{x^2 -1}{2x + 1}}{x}$

$\frac{x^2 -1}{(2x+1) x}$

Now

$\int\limits^2_0 {\frac{x^2 +x +1 }{4x^2 +4 + 1} } \, dx$

(Calculation of this it too long and it is hard to type on brainly)

here is the answer though....

= 4/5

=0.8