Which equation represents an exponential function with an initial value of 500? f(x) = 100(5)x f(x) = 100(x)5 f(x) = 500(2)x f(x
2 answers:
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Let one number be x and the other number be y.
The 2 equations are:
x - y = 0.6 --------------- (1)
x/y = 0.6 --------------- (2)
From equation (1):
x - y = 0.6
x = 0.6 + y --------------- Sub into (2)
0.6 + y= 0.6y
y - 0.6y = - 0.6
0.4y = - 0.6
y = -0.6 ÷ 0.4
y = -1.5
Sub y = -1.5 into (1):
x - y = 0.6
x - (-1.5) = 0.6
x + 1.5 = 0.6
x = 0.6 - 1.5
x = - 0.9
Answer: The numbers are -0.9 and -1.5
The 2 equations are:
x - y = 0.6 --------------- (1)
x/y = 0.6 --------------- (2)
From equation (1):
x - y = 0.6
x = 0.6 + y --------------- Sub into (2)
0.6 + y= 0.6y
y - 0.6y = - 0.6
0.4y = - 0.6
y = -0.6 ÷ 0.4
y = -1.5
Sub y = -1.5 into (1):
x - y = 0.6
x - (-1.5) = 0.6
x + 1.5 = 0.6
x = 0.6 - 1.5
x = - 0.9
Answer: The numbers are -0.9 and -1.5