The answer is: " x < -3 " .
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Explanation:
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Given:
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" 9(2x + 1) < 9x – 18 " ;
First , factor out a "9" in the expression on the right-hand side of the inequality:
9x – 18 = 9(x – 2) ;
and rewrite the inequality:
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9(2x + 1) < 9(x – 2) ;
Now, divide EACH SIDE of the inequality by "9" ;
[9(2x + 1)] / 9 < [9(x – 2)] / 9 ;
to get:
2x + 1 < x – 2 ;
Now, subtract "x" and add "2" to each side of the inequality:
2x + 1 – x + 2 < x – 2 – x + 2 ;
to get:
x + 3 < 0 ;
Subtract "3" from EACH SIDE ;
x + 3 – 3 < 0 – 3 ;
to get:
" x < -3 " .
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Step-by-step explanation:
27/4 × 17/3
9/4 × 17/1
153/4
Answer:
16/13
Step-by-step explanation:
Use a calculator lol
Can I have brainliest please
The question is:
Check whether the function:
y = [cos(2x)]/x
is a solution of
xy' + y = -2sin(2x)
with the initial condition y(π/4) = 0
Answer:
To check if the function y = [cos(2x)]/x is a solution of the differential equation xy' + y = -2sin(2x), we need to substitute the value of y and the value of the derivative of y on the left hand side of the differential equation and see if we obtain the right hand side of the equation.
Let us do that.
y = [cos(2x)]/x
y' = (-1/x²) [cos(2x)] - (2/x) [sin(2x)]
Now,
xy' + y = x{(-1/x²) [cos(2x)] - (2/x) [sin(2x)]} + ([cos(2x)]/x
= (-1/x)cos(2x) - 2sin(2x) + (1/x)cos(2x)
= -2sin(2x)
Which is the right hand side of the differential equation.
Hence, y is a solution to the differential equation.
Answer: x= 3/2 and y= 1/2
Step-by-step explanation:
Since both equations are equated to y, you just need to use substitution to create the equation below:
-x+2 = 3x-4
Solve the equation for x:
4x=6
x=6/4=3/2
Plug in x into any one of the given equations to find the value of y:
y=-x+2
y= - (3/2)+2
y= - (3/2)+4/2
y= 1/2
Hope this helps!
