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Naddik [55]
3 years ago
10

I need help with this it is confusing

Mathematics
1 answer:
Gnoma [55]3 years ago
6 0

Answer:

Step-by-step explanation:

First let's assume that this is a linear relationship.  Find the slope, if there is a unique slope.  As we move from the point (-2, -2) to the point (2, 8), x increases by 4 and y increases by 10, so that the slope is m = rise / run, or

m = 10 / 4, or 2.5.  Using the point (2, 8), determine the y-intercept:

8 = 2.5(2) + b, or 8 = 5 + b, so that b = 3.

Then y = 2.5x + 3.  Now test whether another point, such as (6, 18), satisfies this equation:

18 = 2.5(6) + 3, or

18 = 15 + 3   This is true.

So we can conclude that this is a linear relationship, y = 2.5x + 3  (Answer A)

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Solve the following logarithmic equations.<br> log[(x^2 + 2x − 3)^4] = 0
saw5 [17]

Answer:

The solutions are x = 1.24 and x = -3.24

Step-by-step explanation:

Hi there!

First, let´s write the equation:

log[(x² + 2x -3)⁴] = 0

Apply the logarithm property: log(xᵃ) = a log(x)

4 log[(x² + 2x -3)⁴] = 0

Divide by 4 both sides

log(x² + 2x -3) = 0

if log(x² + 2x -3) = 0, then  x² + 2x -3 = 1 because only log 1 = 0

x² + 2x -3 = 1

Subtract 1 at both sides of the equation

x² + 2x -4 = 0

Using the quadratic formula let´s solve this quadratic equation:

a = 1

b = 2

c = -4

x = [-b± √(b² - 4ac)]/2a

x =  [-2 + √(4 - 4(-4)·1)]/2 = 1.24

and

x = [-2 - √(4 - 4(-4)·1)]/2 = -3.24

The solutions are x = 1.24 and x = -3.24

Have a nice day!

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3 years ago
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