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stepan [7]
3 years ago
12

Paisley has 8\tfrac{1}{4}8 4 1 ​ cups of yogurt to make smoothies. Each smoothie uses \tfrac{11}{16} 16 11 ​ cup of yogurt. How

many smoothies can Paisley make with the yogurt?
Mathematics
1 answer:
Ivenika [448]3 years ago
6 0

Given:

Total Yogurt = 8\dfrac{1}{4} cups

Yogurt required for each smoothie = \dfrac{11}{16} cup

To find:

The number of smoothies that Paisley can make with the yogurt.

Solution:

We know that,

\text{Number of smoothies}=\dfrac{\text{Total yogurt}}{\text{Yogurt required for each smoothie}}

Substituting the given values, we get

\text{Number of smoothies}=\dfrac{8\dfrac{1}{4}}{\dfrac{11}{16}}

\text{Number of smoothies}=8\dfrac{1}{4}\times \dfrac{16}{11}

\text{Number of smoothies}=\dfrac{32+1}{4}\times \dfrac{16}{11}

\text{Number of smoothies}=\dfrac{33}{4}\times \dfrac{16}{11}

\text{Number of smoothies}=3\times 4

\text{Number of smoothies}=12

Therefore, the number of smoothies is 12.

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Two lighthouses are located 75 miles from one another on a north-south line. If a boat is spotted S 40o E from the northern ligh
yuradex [85]

Answer:

The northern lighthouse is approximately 24.4\; \rm mi closer to the boat than the southern lighthouse.

Step-by-step explanation:

Refer to the diagram attached. Denote the northern lighthouse as \rm N, the southern lighthouse as \rm S, and the boat as \rm B. These three points would form a triangle.

It is given that two of the angles of this triangle measure 40^{\circ} (northern lighthouse, \angle {\rm N}) and 21^{\circ} (southern lighthouse \angle {\rm S}), respectively. The three angles of any triangle add up to 180^{\circ}. Therefore, the third angle of this triangle would measure 180^{\circ} - (40^{\circ} + 21^{\circ}) = 119^{\circ} (boat \angle {\rm B}.)

It is also given that the length between the two lighthouses (length of \rm NS) is 75\; \rm mi.

By the law of sine, the length of a side in a given triangle would be proportional to the angle opposite to that side. For example, in the triangle in this question, \angle {\rm B} is opposite to side \rm NS, whereas \angle {\rm S} is opposite to side {\rm NB}. Therefore:

\begin{aligned} \frac{\text{length of NS}}{\sin(\angle {\rm B})} = \frac{\text{length of NB}}{\sin(\angle {\rm S})} \end{aligned}.

Substitute in the known measurements:

\begin{aligned} \frac{75\; \rm mi}{\sin(119^{\circ})} = \frac{\text{length of NB}}{\sin(21^{\circ})} \end{aligned}.

Rearrange and solve for the length of \rm NB:

\begin{aligned} & \text{length of NB} \\ =\; & (75\; \rm mi) \times \frac{\sin(21^{\circ})}{\sin(119^{\circ})} \\ \approx\; & 30.73\; \rm mi\end{aligned}.

(Round to at least one more decimal places than the values in the choices.)

Likewise, with \angle {\rm N} is opposite to side {\rm SB}, the following would also hold:

\begin{aligned} \frac{\text{length of NS}}{\sin(\angle {\rm B})} = \frac{\text{length of SB}}{\sin(\angle {\rm N})} \end{aligned}.

\begin{aligned} \frac{75\; \rm mi}{\sin(119^{\circ})} = \frac{\text{length of SB}}{\sin(40^{\circ})} \end{aligned}.

\begin{aligned} & \text{length of SB} \\ =\; & (75\; \rm mi) \times \frac{\sin(40^{\circ})}{\sin(119^{\circ})} \\ \approx\; & 55.12\; \rm mi\end{aligned}.

In other words, the distance between the northern lighthouse and the boat is approximately 30.73\; \rm mi, whereas the distance between the southern lighthouse and the boat is approximately 55.12\; \rm mi. Hence the conclusion.

4 0
2 years ago
Evaluate the expression a3 -b/c for a = 3, b = 2 and c = 4. write in simplest form
Scilla [17]
Hello There!

Write out your equation:
(a^3 - b)/c
Substitute the values in:
(3^3 - 2)/4
Simplify:
(27 - 2)/4
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Solve:
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Therefore, your answer is 6 1/4.

Hope This Helps You!
Good Luck :) 

- Hannah ❤

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3 years ago
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It’s c counting your heartbeats
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Answer:

1/2 most likely everyone says "half" instead on "point five"

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