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Eddi Din [679]
3 years ago
8

Write the equation 

Mathematics
2 answers:
Shkiper50 [21]3 years ago
3 0
a)\ the\ slope-intercept\ form:\ y=mx+b\\--------------------------\\m=\frac{2}{3}\Rightarrow y=\frac{2}{3}x+b\\\\the\ point\ (-3;\ 6)\Rightarrow \frac{2}{3}\times(-3)+b=6\\\\-2+b=6\ \ \ \ \ |add\ 2\ to\ both\ sides\\\\b=8\\\\\boxed{y=\frac{2}{3}x+8}


b)\ the\ two-points\ formula:y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)\\-----------------------------\\the\ points:\ (3;-1);\ (5;\ 7)\\\\y-(-1)=\frac{7-(-1)}{5-3}(x-3)\\\\y+1=\frac{7+1}{2}(x-3)\\\\y+1=\frac{8}{2}(x-3)\\\\y+1=4(x-3)\\\\y+1=4x-12\ \ \ \ \ |subtract\ 1\ from\ both\ sides\\\\\boxed{y=4x-13}

musickatia [10]3 years ago
3 0
A. y=2/3x+c
6=((2/3)*-3)+c
6+2.33=c
8.33=c

y=2/3x+8 1/3

B. y=mx+c
m= y2-y1/x2-x1
m= (7--1)/(5-3)
m= 8/2 = 4

7=4x5+c
7-20=c
-13=c

y=4x-13
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Step-by-step explanation:

Given expression is |8-6 i|.

|8-6 i| is a complex expression.

The value of<em> i </em>is –1.

By definition of absolute value, |a+b i|=\sqrt{a^{2}+b^{2}}

Now, substitute |8-6 i| in the above formula.  

\Rightarrow|8-6 i|=\sqrt{8^{2}+(-6)^{2}}  (since <em>i </em>= –1)

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Here is the question !
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Answer:

Step-by-step explanation:

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