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Butoxors [25]
3 years ago
14

Kai charges $7 to walk dogs and $2 to walk 3 dogs. Mrs. Greenson only has $7 but she has three dogs, how many dogs can she affor

d to be walked?
Mathematics
2 answers:
Natali [406]3 years ago
8 0
Mrs. Greenson can afford to walk 9 dogs. With a remainder of $1 left.
Vesna [10]3 years ago
4 0
2 dogs he can walk for 7 dollars
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There was 90 runners in the first half 2/5 dropped out I the second half 2/3 dropped out how many finished the race
Liula [17]

Answer:

18.

Step-by-step explanation:

If there were 90 runners, and in the first half 2/5 of them dropped out, here's how we get those who continued the race in the second half.

1. Firstly we need to calculate how many of them dropped out:

2/5 of 90 = 90 ÷ 5 × 2

2/5 of 90 = 18 × 2

2/5 of 90 = 36

2. Now we have to take away the number of dropped-out runners <u>from</u><u> </u><u>the total number of runners from the beginning of the race</u>:

90 - 36 = 54

Now we are left with 54 runners, 2/3 of which dropped out before the finish line.

1. In order to get the number of runners that finished the race, we first need to see how many of them gave up in the second half:

2/3 of 54 = 54 ÷ 3 × 2

2/3 of 54 = 18 × 2

2/3 of 54 = 36

2. Now we just take away the number of runners that dropped out in the second half <u>from the number on the beginning of the half</u>:

54 - 36 = 18

<em>18 runners finished the race.</em>

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4 years ago
Solve by elimination. 2x+5y=-1 <br> x+2y=0
vazorg [7]

Answer:

2x+5y+1=0

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Step-by-step explanation:

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Want 100 Points??? Then plz help me on my HW. A grocery store advertises cherries on sale for $2 per pound. At a different store
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11 / 2.75 = 4

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Milliw paid $5.50 more than she would have if she bought them on sale. The work should explain the answer. She spent $11 on 2.75 lbs of cheeries when she could've spent half of that on cherries which were on sale.

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