Answer:
1600 integers
Step-by-step explanation:
Since we have a four digit number, there are four digit placements.
For the first digit, since there can either be a 5 or an 8, we have the arrangement as ²P₁ = 2 ways.
For the second digit, we have ten numbers to choose from, so we have ¹⁰P₁ = 10.
For the third digit, since it neither be a 5 or an 8, we have two less digit from the total of ten digits which is 10 - 2 = 8. So, the number of ways of arranging that is ⁸P₁ = 8.
For the last digit, we have ten numbers to choose from, so we have ¹⁰P₁ = 10.
So, the number of integers that can be formed are 2 × 10 × 8 × 10 = 20 × 80 = 1600 integers
<span>f(x) = ax2+bx+c, is quadratic equation
</span><span>function opening downward if the a<0,
</span><span>kf(x) = -x², a= -1<0
so the answer is </span><span>B.kf(x) </span><span>
</span>
Replace x with x+3:
f(x+3) = (x+3)²
which is x² translated 3 units left
