Answer:
The program in C++ is as follows:
#include <iostream>
#include <vector>
using namespace std;
int main(){
vector<int> nums;
int num;
cin>>num;
while(num != -1){
nums.push_back(num);
cin>>num; }
for (auto i = nums.begin(); i != nums.end(); ++i){
cout << *i <<endl; }
return 0;
}
Explanation:
This declares the vector
vector<int> nums;
This declares an integer variable for each input
int num;
This gets the first input
cin>>num;
This loop is repeated until user enters -1
while(num != -1){
Saves user input into the vector
nums.push_back(num);
Get another input from the user
cin>>num; }
The following iteration print the vector elements
<em> for (auto i = nums.begin(); i != nums.end(); ++i){
</em>
<em> cout << *i <<endl; }
</em>
Answer:
The operation of 6*x only executes if x is greater or equal to 0, since x=-10 and -10 is less than 0, the operation does not execute. For this reason, the value of y using this code is None.
Explanation:
In python a function is defined with the syntaxis:
def function(x):
the operation to execute (x)
value to return
In this case, the function is foo and the parameter is x:
def foo(x):
if x>= 0:
return 6*x
The code starts by assigning a value to x. Then, the code asks if the value of x is grater or equal to 0, if this condition is meet, then the code returns the value of 6 times x, if not, then the code does not return a value. In this case, x is -10 and this value is not grater or equal to 0. Given that the condition is not met, then the code stops executing and the value of y is none.
One way that computer networks help to protect data is by backing up the data.
Computer networks are normally formatted to automatically back up all of the data that is stored on them. This protects the data in case of any type of computer system failure.
This gap between user-designer communications <span>can cause a good project to go bad i</span>f the user is not able to process what is required to be fixed in order for the project to run smoothly. The user may have one way of fixing something while the designer has another. In this case, the designer understands how the project fully works while the user does not and this may end up compromising the whole project.
The law that “designers are not users” and “users are not designers” should always be followed.
Answer:
Following are the code to the given question:
#include <iostream>//header file
using namespace std;
int main()//main method
{
int r=26,x,y;//defining integer variable
char c;//defining a character variable
for(x= 1; y<= r; x++)//using for loop for count value
{
for(y= 1; y<= x; y++)//using for loop to convert value in triangle
{
c=(char)(y+64);//convert value into character
cout << c;//print character value
}
cout << "\n";//use print method for line break
}
return 0;
}
Output:
Please find the attachment file.
Explanation:
In this code, three integer variable "x,y, and r", and one character variable "c" is declared, that is used in the nested for loop, in the first for loop it counts the character value and in the next for loop, it converts the value into a triangle and uses the char variable to print its character value.
