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Alex777 [14]
3 years ago
14

4). A bag of marbles can be shared equally among 3,5 or 6 students with none left over what’s the Least amount of marbles that c

an be in the bag?
5). 4/7 of the birthday cake was eaten on your birthday. The next day, your day ate 1/2 of what was left. You get to finish the cake how much was left?
Mathematics
2 answers:
Ivanshal [37]3 years ago
6 0

4.) the bag would have 30 marbles in it

3,5, and 6 can all be divided equally by 30.

5.) 1/14

you would do 4/7-1/2 which equals 1/14

(this one could be wrong im not good with fractions)

DaniilM [7]3 years ago
3 0
Snsn snsn imma mink hunk
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If a rectangular piece of metal has 27.75 square inches what is the length and width?
svp [43]

We cannot get further information about the dimensions of the piece since the number of variables is greater than the number of equations.

<h3>What are the dimensions of a rectangular piece of metal?</h3>

By geometry we know that the area of the piece of metal is equal to the product of its length and width, then we must find two <em>real</em> numbers such that:

l · w = 27.75, where l, w > 0.

Unfortunately, we cannot get further information about the dimensions of the piece since the number of variables is greater than the number of equations. We need at least one equation to find an <em>unique</em> solution.

To learn more on rectangles: brainly.com/question/15019502

#SPJ1

4 0
2 years ago
Which rational graph has a minimum near x=-2 and a horizontal asymptote at y=1?
Arada [10]

Answer:

Graph A.

Step-by-step explanation:

The graph has a local minimum around x=-2 since it slightly curves downwards around this region. Moreover, the graph of the rational function has a horizontal asymptote at y=1 since the graph approaches this horizontal line but never touches nor crosses it

7 0
3 years ago
PLEASE HELP QUICK!!! A bowl has 85 pieces of candy. Nineteen children empty the bowl of candy. Some children take 3 pieces, some
Mekhanik [1.2K]

Answer: 3 kids take 3 pieces of candy each

Step-by-step explanation:

Let the number of children that took 3 pieces is x ( total take 3*x pieces of candy)

Number of children that took 5 pieces is y ( total take 5*y pieces of candy)

1 child took 1 piece that actually means that x+y=18 and 3*x+5*y=84.

( Because total number of all kids is 19. We just deduct one kid (Let his name is John) who took only 1 candy.  So we have 19-1 =18 kids without John. The similar is with the candies. Total number is 85. We deduct 1 piece which John has taken. )

So we have 2 equations or the system of 2 equations:

1).  x+y=18

2). 3*x +5*y=84

Multuply both sides of equation 1) by 3

We have   3*x+3*y=18*3

Deduct 3*y from both sides of this equation

3*x+3*y-3*y=54-3*y

3*x=54-3*y

Substitute 3*x in equation  2).  by 54-3*y

2) 54-3*y+5*y=84

2*y=30

y=15  ( kids take 5 pieces of candy each)

Using equation 1) find x

x+15=18

x=3 (kids take 3 pieces of candy each)

5 0
3 years ago
.help me with this please thanks
aev [14]
I would say B . 
They are not like terms because they are not all the same
5 0
3 years ago
The government of the Republic of Lemon Island plans to transform their lemon-based economy into a tourism-based economy. They d
NNADVOKAT [17]

Step-by-step explanation:

dy/dt = (A − Be^(-t/5)) y

(a) First, find the general solution by separating the variables and integrating.

dy / y = (A − Be^(-t/5)) dt

dy / y = [A + 5B (-⅕ e^(-t/5))] dt

ln |y| = At + 5B e^(-t/5) + C

y = e^(At + 5B e^(-t/5) + C)

y = Ce^(At + 5B e^(-t/5))

Given that A = 0.06, B = 0.04, and y(0) = 50×10⁶ − 10×10⁶ = 40×10⁶:

40×10⁶ = Ce^(0.06(0) + 5(0.04) e^(-0/5))

40×10⁶ = Ce^(0.2)

C = 40×10⁶ e^(-0.2)

y = 40×10⁶ e^(-0.2) e^(0.06t + 0.2 e^(-t/5))

y = 40×10⁶ e^(-0.2 + 0.06t + 0.2 e^(-t/5))

(b) If A = 0.02 and B = 0, and there is no transformation (y(0) = 50×10⁶), then:

50×10⁶ = Ce^(0.02(0) + 0)

50×10⁶ = C

y = 50×10⁶ e^(0.02t)

Comparing to the answer from part (a):

40×10⁶ e^(-0.2 + 0.06t + 0.2 e^(-t/5)) = 50×10⁶ e^(0.02t)

e^(-0.2 + 0.04t + 0.2 e^(-t/5)) = 5/4

-0.2 + 0.04t + 0.2 e^(-t/5) = ln(5/4)

-5 + t + 5e^(-t/5) = 25 ln(5/4)

t + 5e^(-t/5) = 5 + 25 ln(5/4)

Solve with a calculator:

t = 9.886

The transformed economy surpasses the untransformed economy in the 10th year.

(c) In year t=5, the size of the transformed economy is:

y = 40×10⁶ e^(-0.2 + 0.06(5) + 0.2 e^(-5/5))

y = 47.6×10⁶

The percent growth is:

(47.6×10⁶ − 40×10⁶) / 40×10⁶ × 100% = 19%

The growth rate is greater than 4%, so the current government can expect to be reelected.

3 0
3 years ago
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