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3 years ago

a parallelogram has a base of 12 inches. If its area is 96 square inches, find the height of the parallelogram.

1 answer:

3 0

A=bh => h=A/b

A=96 in^2
b=12 in
h=A/B=96 in^2/12 in = 96/12 in = 8 in.

Height = 8 inches

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kati45 [8]

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$\left \{ {{A(2)+B(-1)=1} \atop {A(-3)+B(-2)=1}} \right. \\\\=\left \{ {{2A-B=1} \atop {-3A-2B=1}} \right.$

Find the value of B from the equation 2A - B = 1:

$2A-B=1\\-B=1-2A\\B=2A-1$

Substitute in the B-value to the other equation:

$-3A-2B=1\\-3A-2(2A-1)=1\\-3A-4A+2=1\\-7A=1-2\\-7A=-1\\A=\frac{-1}{-7} =\frac{1}{7}$

Find the B-value using the equation from before:

$B=2A-1=2(\frac{1}{7})-1=\frac{2}{7} -\frac{7}{7} =-\frac{5}{7}$

Therefore the equation Ax + By = 1 would equal:

$\frac{1}{7} x-\frac{5}{7} y=1$

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