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Savatey [412]
3 years ago
5

The perimeter of a triangle is 6x. One side is x+3 and another side is 2x+4. What is the length of the 3rd side?

Mathematics
1 answer:
maxonik [38]3 years ago
6 0
Let y = the length of the 3rd side
x+3 + 2x+4 + y = 6x
x + 2x + 3 + 4 + y = 6x
3x + 7 +y = 6x
7 + y = 3x
y = 3x - 7
The length of the third side in terms of x is 3x-7
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Answer:

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Step-by-step explanation:

the slope-intercept form is y = ax+b

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Assignment: \bold{Solve \ Equation: \ \left(x^2-9x+2\right)+\left(4x^2-5x+1\right)-\left(5x^2-5\right)}

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Answer: \boxed{\bold{-14x+8}}

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Explanation: \downarrow\downarrow\downarrow

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[ Step One ] Remove Parenthesis: (a) = a

\bold{x^2-9x+2+4x^2-5x+1-\left(5x^2-5\right)}

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[ Step Three ] Rewrite Equation

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[ Step Four ] Simplify \bold{x^2-9x+2+4x^2-5x+1-5x^2+5}

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\bold{\rightarrow Mordancy \leftarrow}

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Step-by-step explanation:

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