All categories

3 years ago

-5x-12= 13 (find the x)

Mathematics

2 answers:

prisoha [69]3 years ago

7 0

Answer:

-5

Step-by-step explanation:

-5x-12= 13 add 12 to both sides

-5x-12 + 12= 13 + 12 ➡ -5x = 25 divide both sides by 5

-5x ÷ 5 = 25 ÷ 5 ➡ -x = 5 and x = -5

azamat3 years ago

4 0

Answer:

-5

Step-by-step explanation:

-5x-12=13

+12. +12

-5x=25

÷-5=÷-5

x=-5

You might be interested in

A pyramid is 24 ft tall. A scaled model has a height of 2ft and is 1 foot wide at the base. Identify the scale factor that was u

il63 [147K]

Answer:

1/12

Step-by-step explanation:

Given the following :

Actual height of pyramid = 24 ft

Dimension of scaled model :

Height = 2ft ; width = 1ft

The scale factor is a number used to reproduce a reduced dimension of a model by multiplying the actual dimeznsion or size of the model or object.

Since the height is of the scaled model is less than the actual height of the pyramid ; then it could be said that the scale factor is a fraction, because reduction has occurred.

(Height of scaled model / height of actual pyramid)

(2ft / 24ft) = 1/12

8 0

3 years ago

Help me plzzzzzzzzzzzzzzzzzzz

lubasha [3.4K]

Answer:

Step-by-step explanation:

irdk sorry if its wrong :(

5 0

3 years ago

What is the x value when g(x)=1 PLS HELP

olga_2 [115]

Answer:

I believe the answer is x=1.

Step-by-step explanation:

I am a bit confused on what is wanted, but g(x) is the x value on the line g. so when g(x)=1, I think x=1 on the line g.

3 0

3 years ago

Given P space equals space P subscript 0 space plus space rho g h, your objective is to determine the uncertainty of P by measur

son4ous [18]

Answer:

the g's contributing term for the overall uncertainty of P is $dP_g = [\frac{dg}{g}]$

Step-by-step explanation:

From the question we are told that

The pressure is $P = P_o + \rho gh$

The first step in determining the uncertainty of P in by obtaining the terms in the equation contributing to it uncertainty and to do that we take the Ln of both sides of the equation

$ln P = lnP_o + ln(\rho gh )$

=> $ln P = lnP_o + ln \rho + ln g + ln h$

Then the next step is to differentiate both sides of the equation

$\frac{d(ln P)}{dP} = \frac{d(ln P_o)}{dP_o} + \frac{d(ln \rho)}{d\rho} +\frac{d(ln g)}{dg} + \frac{d(ln h)}{dh}$

=> $\frac{dP}{P} = \frac{dP_o}{P_o} + \frac{d \rho}{\rho} +\frac{d g}{g} + \frac{d h}{h}$

We asked to obtain the contribution of the term g to the uncertainty of P

This can deduced from the above equation as

$dP_g = [\frac{dg}{g}] P$

8 0

4 years ago

PLEASE help me with this question and I WILL love you forever But yeah please help me with the question.And EXPLAIN in words how

Rufina [12.5K]

Well on this problem recall area of a rectangle is defined by:

A = lw our w = 1/6 and our l = (x + $\frac{2}{3}$ ) we have let 'x' represent our original length.
$(x + \frac{2}{3} )( \frac{1}{6} )= \frac{11}{72}$
$\frac{1}{6} x+ \frac{2}{18} = \frac{11}{72}$
12x + 8 = 11
12x = 11 - 8
12x = 3
x = $\frac{3}{12} = \frac{1}{4}$ So our original length is $\frac{1}{4}$

5 0

4 years ago