Answer:
C and B.
Step-by-step explanation:
f(x) = 4 - x^2.
The degree of f(x) is 2, which means it is a quadratic graph. The coefficient of x^2 is negative, which means the curve is pointing downwards. The only curve that satisfies this is Graph C.
f(x) = 2^x + 5.
Notice that 2^x is positive for all real values of x. Therefore the answer is Graph B.
Answer:
The zeroes are -6, 1/2 and 2.
Step-by-step explanation:
f(x) = 2x3 + 7x2 - 28x + 12 = 0
From the first and last coefficient 2 and 12, one guess for a zero is x = 2.
So substituting x = 2:
f(2) = 16+ 28 - 56 + 12 = 0
So x = 2 is a zero and x - 2 is a factor of f(x)
Performing long division:
x - 2)2x3 + 7x2 - 28x + 12( 2x2 + 11x - 6 <------- Quotient
2x3 - 4x2
11x2 - 28x
11x2 - 22x
- 6x + 12
-6x + 12
.............
Now we solve
2x2 + 11x - 6 = 0
(2x - 1)(x + 6) = 0
2x - 1 = 0 or x + 6 = 0, so:
x = 1/2, x = -6.
Answer:I think it’s 16 because 4x4=16
Step-by-step explanation: :D
Answer:
w = ±![\sqrt[4]{36/5}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B36%2F5%7D)
Step-by-step explanation:
-8+5w^4=28
You can regroup it:
5w^4 - 8 = 28
Add 8 to both side:
5w^4 = 28 + 8
5w^4 = 36
Divide both side by 5:
5w^4/5 = 36/5
w^4 = 36/5
Take the 4 root of both sides:
w = ±
Hope this help you :3
Rather than memorize sines and cosines of various common triangles, I prefer to remember the simple derivation of those formulas…
Imagine that the wall is a mirror, so you have one ladder leaning against the wall and you also have the reflection of that ladder leaning behind it. Now the ladder is 6m long, its reflection is 6m long, and if the distance between their bases is also 6m then you have a 60–60–60 equilateral triangle. And, good news, the problem says that the base angle is 60 degrees. So the real part in front of the mirror is half of the equilateral triangle, which means the distance from the base to the mirror is 3m. And then the height is sqrt(36–9) = sqrt(27) = 3*sqrt(3).
