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zepelin [54]
3 years ago
9

Add my s. n. a. p. c. h. a. t. its kribbytheking i add back .

Mathematics
1 answer:
romanna [79]3 years ago
4 0
Ahhh bet your a female right?
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Would I use the volume formula and what answer would I get?
jeka94
V=4/3pi(5)3
v=166.7 pi n^3
V= 523.7 or 523.6in ^3
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4 years ago
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Angle ACD is supplementary to angles ACE and BCD and congruent to angle BCE.
Andrew [12]

Answer:

Step-by-step explanation:

Angle BCE is supplementary to angle ACE.

Angle BCD is supplementary to angle BCE.

Angle BCD is congruent to angle ACE

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INEQUALITIES <br> How can i graph 2x - 5 + 4x &gt; 2x - 1 on a number (or cartesian) plane.
zubka84 [21]
So you need to replace X with a number, let’s say 4 in this example. 2 x 4 - 5 + 4 x 4 > 2 x 4 - 1 which is basically 19>7
7 0
2 years ago
Which values represent the first two terms of the sequence a1=2 and an=-2(an-1)^2?
Mars2501 [29]
Hello,

a_{1}=2
a_{n+1}=-2*a_{n}^2

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Answer C






3 0
3 years ago
In the box, complete the first 4 steps for graphing the quadratic function given. (Use ^ on the keyboard to indicate an exponent
Vaselesa [24]
Step 1: convert the equation into fhe vertex form

To do you can complete squares:

y = - [x^2 + 4x + 3]

y = - [ (x + 2)^2 - 4 + 3]

y = - [ (x + 2)^2 - 1] = - (x+2)^2 + 1

Then the vertex is (-2, 1)

Now you can drasw the vertex


Step 2: Find the roots (zeros)

y = - [ (x + 2)^2 - 1] = 0

(x + 2)^2 - 1 = 0

(x+2)^2 = 1

(x+2) = (+/-) √1

x + 2 = (+/-1)

x = - 2 +/- 1

x = -1 and x = -3

Now you draw the points (-1,0) , (-3,0)

Step 3: find the interception with the y-axis.

That is y value when x = 0

y = - (0)^2 - 4(0) - 3 = -3

Then draw the point (0, -3)

Step 4: given that the coefficent of x is negative (-1) the parabola is open downward.

So, with those four points: vertex (-2,1), (-1,0), (-3,0) and (0,-3), you can sketch the function.
7 0
3 years ago
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