Answer:
1/5
Step-by-step explanation:
0.2
=2/10
=1/5
One is colder than the other.
Hope this helps :)
Answer:
<em>He will need 51 yards, 1 foot and 8 inches twine to wrap 29 cartons. </em>
Step-by-step explanation:
Muhammad uses 1 yard, 2 feet and 4 inches of twine to wrap each carton he packs.
<u>We know that, 1 yard = 36 inches and 1 foot = 12 inches</u>.
So, 1 yard, 2 feet and 4 inches ![=[(1*36)+(2*12)+4]inches = 64](https://tex.z-dn.net/?f=%3D%5B%281%2A36%29%2B%282%2A12%29%2B4%5Dinches%20%3D%2064)
inches.
That means, he uses 64 inches of twine to wrap each carton.
He has to pack 29 cartons today. So, <u>the total length of the twine he will need</u> 
inches.
Now....
1856 inches
Thus, he will need 51 yards, 1 foot and 8 inches twine to wrap 29 cartons.
(i) The area of the cross section ABCDEFG is 1771.6cm³
(ii) The volume of the concrete lab is 212592 cm³
(iii) the total surface area of the concrete slab is 30284 cm²
(iv) The mass of the concrete slab is 40746.8 kg/m³.
Given, dimensions are 120 cm by 60 cm by
40 cm.
(i) area of cross section = 40 × 60 ₋ π(60 ₋10 ₋ 10)/2 . 1/2
= 1771.6 cm³
(ii) the volume of the concrete slab = 40 × 60 × 120 ₋ 1/2 π((60 ₋ 10 ₋10)/2)² . 120
= 212592 cm³
(iii) The total surface area is:
=40 × 120 × 2 ₊ 60 × 120 ₊ 1771.6 × 2 ₊ 10 × 120 × 2 ₊ 1/2 π(60 ₋ 10 ₋10) × 120
= 30284 cm²
(iv) Mass of the concrete slab given density is 2300 kg/m³
Mass = Volume × density
Mass = 17.716 m³ × 2300
= 40746.8 kg/m³
Hence we get the mass as 40746.8 kg/m³.
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Answer:
a and b
Step-by-step explanation:
