Answer:
Explanation:
def octal_to_string(octal):
result = ''
value_letters = [(4, 'r'), (2, 'w'), (1, 'x')]
for c in [int(n) for n in str(octal)]:
for value, letter in value_letters:
if c >= value:
result += letter
c -= value
else:
result += '-'
return result
print(octal_to_string(755))
print(octal_to_string(644))
print(octal_to_string(750))
print(octal_to_string(600))
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Answer:
True
Explanation:
according to coursehero it's true
N = 0
<span>1 read x </span>
<span>n = n + 1 </span>
<span>print x </span>
<span>If n > 1, go down to 2 </span>
<span>small = x </span>
<span>large = x </span>
<span>2 If x</= small, then small = x </span>
<span>If x>/= large, then large = x </span>
<span>If n < 12 , go back up to 1 </span>
<span>Print small </span>
<span>Print large </span>
<span>end</span>
Answer:
total=0
pet=input("what pet do you have? ")
while pet!= "rock":
total=total+1
print("you have a "+pet+" with a total of "+ str(total)+ " pet(s)")
pet=input("What pet do you have? ")
Explanation: Just copy and paste above again just copy and paste this will get you a 100 percent i made another account just to give yall edhesive answers if yall need help with any edhesive just comment below
