3 years ago

Function or not? I will give you brainliest Pls help, Thank you

Mathematics

1 answer:

Anestetic [448]3 years ago

3 0

Function:)hope this helped

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3x+2=3x+2<br> Is this one solution, no solution, or infinite solution

TiliK225 [7]

Answer:

infinite solution

Step-by-step explanation:

no matter what you have for x, 3x still equals 3x, so it is infinite

6 0

3 years ago

What’s the quotient of 2 divided by 1/3

just olya [345]

2 4/5 divided by 1 1/3
= 14/5 divided by 4/3
= 14/5 * 3/4
= 42/20
= 21/10
= 2 1/10
Final Answer: 2 1/10

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3 years ago

Find the value of x. Round the answer to the nearest tenth, if needed. A. 4.8 B. 5.1 C. 8.2 D. 9.5

tatuchka [14]

We need the actual problem/diagram or whatever to solve this

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3 years ago

For the linear equation y = -2x - 4, find the missing coordinate (3, ____)

nekit [7.7K]

Answer:

y=-10

Step-by-step explanation:

y=-2(3)-4

y=-10

8 0

2 years ago

Use Lagrange multipliers to find the maximum and minimum values of f(x,y)=x+4y subject to the constraint x2+y2=9, if such values

Vesnalui [34]

The Lagrangian is

$L(x,y,\lambda)=x+4y+\lambda(x^2+y^2-9)$

with critical points where the partial derivatives vanish.

$L_x=1+2\lambda x=0\implies x=-\dfrac1{2\lambda}$

$L_y=4+2\lambda y=0\implies y=-\dfrac2\lambda$

$L_\lambda=x^2+y^2-9=0$

Substitute $x,y$ into the last equation and solve for $\lambda$ :

$\left(-\dfrac1{2\lambda}\right)^2+\left(-\dfrac2\lambda\right)^2=9\implies\lambda=\pm\dfrac{\sqrt{17}}6$

Then we get two critical points,

$(x,y)=\left(-\dfrac3{\sqrt{17}},-\dfrac{12}{\sqrt{17}}\right)\text{ and }(x,y)=\left(\dfrac3{\sqrt{17}},\dfrac{12}{\sqrt{17}}\right)$

We get an absolute maximum of $3\sqrt{17}\approx12.369$ at the second point, and an absolute minimum of $-3\sqrt{17}\approx-12.369$ at the first point.

4 0

3 years ago