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Ratling [72]
2 years ago
11

In circle G with m \angle FGH= 42m∠FGH=42 and FG=6FG=6 units find area of sector FGH. Round to the nearest hundredth.

Mathematics
1 answer:
erastovalidia [21]2 years ago
5 0

The area of the sector with a radius of 6units and an angle of 4 degrees rounded to the nearest hundredth is 13.19 square units

<h3>How to find the area of a sector?</h3>

The sector is a part of a circle with an angle subtended at the centre. The formula for calculating the area of a sector is expressed as:
A = r²Ф/2

where:

r is the radius

Ф is the subtended angle

Given the following

r = 6 units

Ф = 42degres

<h3>Substitute</h3>

Area of the sector = 6²/2 * 42/180 π
Area of the sector = 13.188units

Hence the area of the sector rounded to the nearest hundredth is 13.19 square units

Learn more on area of sector here: brainly.com/question/22972014

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kaheart [24]

Answer:

- x as a linear combination :

x = -1 v1+ 0 v2+ 1 v3.

- Transpose Ax = (12, -6, -6)

Step-by-step explanation:

Given v1 = (0 3 3),v2 = (1 −1 0), v3 = (3 0 −3) be eigenvectors of the matrix A which correspond to the eigenvalues λ1 = −1, λ2 = 0, and λ3 = 1, respectively, and let x = (−2 −4 0). Express x as a linear combination of v1, v2, and v3, and find Ax .

To write x as a linear combination of v1, v2, and v3

x = -1 v1+ 0 v2+ 1 v3.

To find Ax

Write A = (0 ......3 ......3 )

...................(1 ......-1 ......0)

...................(3 ......0......-3)

Since transpose x = (-2, 4, 0)

Ax =......... (0 ......3......3 )(-2)

...................(1 ......-1 ......0)(4)

...................(3 ......0......-3)(0)

= (0×-2 + 3×4 + 3×0)

...(1×-2 + -1×4 + 0×0)

.. (3×-2 + 0×4 + -3×0)

As = (12)

....(-6)

....(-6)

Transpose Ax = (12, -6, -6)

7 0
3 years ago
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OverLord2011 [107]

Answer:

1=120

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5=300

Step-by-step explanation:

i used a calculator

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Answer:

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