In circle G with m \angle FGH= 42m∠FGH=42 and FG=6FG=6 units find area of sector FGH. Round to the nearest hundredth.

1 answer:

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The area of the sector with a radius of 6units and an angle of 4 degrees rounded to the nearest hundredth is 13.19 square units

<h3>How to find the area of a sector?</h3>

The sector is a part of a circle with an angle subtended at the centre. The formula for calculating the area of a sector is expressed as:
A = r²Ф/2

where:

r is the radius

Ф is the subtended angle

Given the following

r = 6 units

Ф = 42degres

<h3>Substitute</h3>

Area of the sector = 6²/2 * 42/180 π
Area of the sector = 13.188units

Hence the area of the sector rounded to the nearest hundredth is 13.19 square units

Learn more on area of sector here: brainly.com/question/22972014

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If x has a mean of 17.2 g and a standard division of 14.0 g and y has a mean of 23.5 g and a standard division of 16.4 g and the

dimulka [17.4K]

The least squares regression line is y=0.6831x+11.25

Step-by-step explanation:

LSRL is the the Least Squares Regression Line.The formula for regression line is y=mx+b where m is the slope of the line and b is the y-intercept value of the line.

First find the slope, m of the line from the means and standard deviations given

x has a mean of 17.2 g and a standard deviation of 14.0 g

y has a mean of 23.5 g and a standard deviation of 16.4 g

The correlation coefficient in both cases is 0.83, hence the slope m is given by;

m=r(Sy/Sx) where m is the slope of the line, Sy is standard deviation of y values, Sx is standard deviation of x values and r is the correction coefficient.

m= 0.5 * 23.5/17.2 =0.6831

Find the value of b, the y-intercept

b=Y-mX where X and Y are the mean values for x and y respectively

b=23.5-0.6831*17.2

b=23.5-11.75=11.25

The LSRL is y=0.6831x+11.25

Learn More

Least Squares regression Line : brainly.com/question/4090838

Keyword : standard deviation, least square regression line

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