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Mice21 [21]
3 years ago
14

Two of the vertices of a rectangle are (6,1) and (7,1) . IF the rectangle has a perimeter of 18 units, then what are the coordin

ates of its other two vertices
Mathematics
1 answer:
fenix001 [56]3 years ago
3 0

Answer:

(6 , -9) (7, -9)

Or

(6, 11) (7, 11)

Step-by-step explanation:

Given: Two of the vertices of a rectangle are (6,1) and (7,1)

Perimeter= 18 units

To get the value of "x"

The distance between Two point can be calculated as (6-7)=-1

Then x= -1

We can get the value of "y" by using expression for perimeter,

The perimeter P= 2x+2y=18

= 2(-1)+2y= 18

-2+2y=18

2y=18+2

2y= 20

y=10

The "y" coordinate can move up or can move down

y1=( 1-10)=-9

Or

y2=( 1+10)=11

Hence, the two other points are;

(6 , -9) (7, -9)

Or

(6, 11) (7, 11)

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MrMuchimi
When x = 0

A. 0, 7 is your answer

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4 0
3 years ago
S = 1 / g t ² π, solve for t​
Finger [1]

s =   \frac{1}{g {t}^{2}\pi }

multiply through by

g {t}^{2} \pi

s \times g {t}^{2} \pi =  \frac{1}{g {t}^{2} \pi}  \times g {t}^{2} \pi

sg {t}^{2} \pi = 1

dividing through by

sgπ

{t}^{2}  =  \frac{1}{sg\pi}

t =  \sqrt{ \frac{1}{sg\pi} }

4 0
3 years ago
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How to solve for x and what does x equal in this?​
Tanya [424]

Answer:

10

Step-by-step explanation:

give brainliest please!

hope this helps :)

so these two angles add up to 180 degrees

7x -3 + 12x -7 = 180

7x+12x=180+7+3

19x=190

x=10

to check if this is true we can input 10 for x in each side.

7(10)-3 = 67

12(10)-7 = 113

113+67 = 180

7 0
2 years ago
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Mia discovered that if she takes half her age and adds 3, it produces the same results as taking one-fourth of her age and addin
Vikentia [17]

See https://web2.0calc.com/questions/help_29833.

5 0
3 years ago
Find the LCM of n^3 t^2 and nt^4.<br><br> A) n 4t^6<br> B) n 3t^6<br> C) n 3t^4<br> D) nt^2
patriot [66]

Answer:

The correct option is C.

Step-by-step explanation:

The least common multiple (LCM) of any two numbers is the smallest number that they both divide evenly into.

The given terms are n^3t^2 and nt^4.

The factored form of each term is

n^3t^2=n\times n\times n\times t\times t

nt^4=n\times t\times t\times t\times t

To find the LCM of given numbers, multiply all factors of both terms and common factors of both terms are multiplied once.

LCM(n^3t^2,nt^4)=n\times n\times n\times t\times t\times t\times t

LCM(n^3t^2,nt^4)=n^3t^4

The LCM of given terms is n^3t^4. Therefore the correct option is C.

8 0
3 years ago
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