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Mice21 [21]
3 years ago
14

Two of the vertices of a rectangle are (6,1) and (7,1) . IF the rectangle has a perimeter of 18 units, then what are the coordin

ates of its other two vertices
Mathematics
1 answer:
fenix001 [56]3 years ago
3 0

Answer:

(6 , -9) (7, -9)

Or

(6, 11) (7, 11)

Step-by-step explanation:

Given: Two of the vertices of a rectangle are (6,1) and (7,1)

Perimeter= 18 units

To get the value of "x"

The distance between Two point can be calculated as (6-7)=-1

Then x= -1

We can get the value of "y" by using expression for perimeter,

The perimeter P= 2x+2y=18

= 2(-1)+2y= 18

-2+2y=18

2y=18+2

2y= 20

y=10

The "y" coordinate can move up or can move down

y1=( 1-10)=-9

Or

y2=( 1+10)=11

Hence, the two other points are;

(6 , -9) (7, -9)

Or

(6, 11) (7, 11)

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The Sunday Times had 14 sections with an average of 16 pages per section. How many pages were in the entire newspaper?
Gennadij [26K]

Answer:

224 pages total

Step-by-step explanation:

To find how many total pages, you have to multiply the number of sections by the number of pages in each section. 14 sections times 16 pages per section equals a total of 224 total pages.

7 0
3 years ago
We measure the diameters for a random sample of 25 oak trees in a neighbourhood. Diameters of oak trees in the neighbourhood fol
jarptica [38.1K]

Answer:

The required confidence inteval = 94.9%.

Step-by-step explanation:

Confidence interval: Mean ± Margin of error

Given: A confidence interval for the true mean diameter of all oak trees in the neighbourhood is calculated to be (36.191, 42.969).

i.e.  Mean + Margin of error = 42.969               (i)

Mean - Margin of error = 36.191                    (ii)

Adding (i) and (ii), we get

2Mean =79.16\\\\\Rightarrow\ Mean= 39.58

Margin of error = 42.969-39.58             [from (i)]

= 3.389

Margin of error = t^* \dfrac{\sigma}{\sqrt{n}}

here n= 25 , \ \sigma=8.25

i.e.

3.389=t^*\dfrac{8.25}{5}\\\\\Rightarrow\ t^* = \dfrac{3.389}{1.65}\\\\\Rightarrow\ t^* =2.0539 \

Using  excel function 1-TDIST.2T(2.054,24)

The required confidence inteval = 94.9%.

7 0
3 years ago
An urn contains 2 red marbles and 3 blue marbles. 1. One person takes two marbles at random from the urn and does not replace th
Ghella [55]

Answer:

A) The best way to picture this problem is with a probability tree, with two steps.

The first branch, the person can choose red or blue, being 2 out of five (2/5) the chances of picking a red marble and 3 out of 5 of picking a blue one.

The probabilities of the second pick depends on the first pick, because it only can choose of what it is left in the urn.

If the first pick was red marble, the probabilities of picking a red marble are 1 out of 4 (what is left of red marble out of the total marble left int the urn) and 3 out of 4 for the blue marble.

If the first pick was the blue marble, there is 2/4 of chances of picking red and 2/4 of picking blue.

B) So a person can have a red marble and a blue marble in two ways:

1) Picking the red first and the blue last

2) Picking the blue first and the red last

C) P(R&B) = 3/5 = 60%

Step-by-step explanation:

C) P(R&B) = P(RB) + P(BR) = (2/5)*(3/4) + (3/5)*(2/4) = 3/10 + 3/10 = 3/5

3 0
3 years ago
Drew invests $70.00. It earns 50% interest annually.
VladimirAG [237]

Step-by-step explanation:

50% interest annually.

that means he gets 50% interest of the invested capital every year.

and that means he gets 50% of $70 in one year.

70 = 100%

1% = 100%/100 = 70/100 = $0.70

50% = 1%×50 = 0.7 × 50 = $35

he will earn $35 interest in one year.

as you noticed: 50% simply means 1/2 (as 100% stands for the whole).

3 0
1 year ago
The line plot below shows the weight of each of 15 ostrich eggs . What is the total weight of the 3 heaviest eggs
erica [24]

Answer:

D). 6 3/4

Step-by-step explanation:

Given,

The three eggs with the heaviest weights are;

2\frac{1}{2} ounces

2\frac{1}{4} ounces, &

2 ounces

To find,

The total weight of the three heaviest eggs = 2\frac{1}{2} ounces + 2\frac{1}{4} ounces + 2 ounces

= 5/2 + 9/4 + 2/1

Taking the L.C.M. of 2, 4, and 1,

= 10/4 + 9/4 + 8/4

= (10 + 9 + 8)/4

= 27/4 or 6 3/4

4 0
3 years ago
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