Answer:
y = 115.0977+12.2992X
91.59%
Step-by-step explanation:
Given :
DLH(X) ILE(Y)
20 361_0
25 400
22 376
23 384
20 361_0
19 360
24 427.2
28 458.4
26 450_8
29 475.2
DLH (X) : Direct Labor Hours
ILE (Y) : Indirect Labor Expense
The regression model obtained by fitting the data using technology is :
y = 115.0977+12.2992X
Where ;
Intercept = 115.0977 ;
Slope = 12.2992
The Coefficient of determination, R² gives the proportion of explained variance due to the regression line.
For the data given above, the Coefficient of determination R² obtained using the Coefficient of determination calculator is 0.9159 ; which means that (0.9159 * 100%) about 91.59% of the variation in indirect labor expense is explained by the regression line while 8.41% is due to other factors.
The student will have $135 in her bank account at the end of the ninth week. You can fine this out by finding out the amount she deposits a week and to do this you would take the $30 and divide it by 2 because she had $30 at the end of the second week.
30/2=15
So you see that the student deposits $15 each week, so to find out how much money she will have in 9 weeks you will multiply her $15 by 9.
15x9=135
So the student will have $135 at the end of the ninth week.
Answer:
The degrees of freedom are given by:
The p value for this case would be given by:
Since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not ignificantly lower than 5 minutes
Step-by-step explanation:
Information given
represent the sample size
represent the confidence level
represent the sample variance
represent the value that we want to verify
System of hypothesis
We want to test if the true deviation for this case is lesss than 5minutes, so the system of hypothesis would be:
Null Hypothesis: 
Alternative hypothesis: 
The statistic is given by:
And replacing we got:
The degrees of freedom are given by:
The p value for this case would be given by:
Since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not ignificantly lower than 5 minutes
Can you please take a better picture please
