3 years ago

Angle relationships with parallel lines

Mathematics

2 answers:

Naddik [55]3 years ago

7 0

Answer: 136°

Step-by-step explanation:

In this angle relationship, it is a supplementary angles. because the parallel lines are separated by a line, the 2 angles make 180°.

180°=44°+x°

x=136°

LekaFEV [45]3 years ago

4 0

180-44= 136

so x=136

You might be interested in

Using the numbers 5, 8, and 24, create a problem using no more than 4 operations (adding, subtracting, multiplication, division,

nalin [4]

<span>√(5*8*24) or anything along those lines, you can switch the numbers around , it wont matter</span>

3 0

3 years ago

Sin(60-theta)sin(60+theta)

ehidna [41]

Step-by-step explanation:

$\sin(60 - \theta) \sin(60 + \theta) \\ = \{ \sin(60) \cos( \theta) - \sin( \theta) \cos(60) \} \{ \sin(60) \cos( \theta) + \cos(60) \sin( \theta) \} \\ = \{ \frac{ \sqrt{3} }{2} \cos( \theta) - \frac{1}{2} \sin( \theta) \} \{ \frac{ \sqrt{3} }{2} \cos( \theta) + \frac{1}{2} \sin( \theta) \} \\ \\$

from difference of two squares:

${ \boxed{(a - b)(a + b) = ( {a}^{2} - {b}^{2} ) }}$

therefore:

$= \{ {( \frac{ \sqrt{3} }{2}) }^{2} { \cos }^{2} \theta \} - \{ {( \frac{ \sqrt{3} }{2} )}^{2} { \sin }^{2} \theta \} \\ \\ = \frac{3}{4} { \cos }^{2} \theta - \frac{3}{4} { \sin}^{2} \theta$