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2 years ago

Heyo yall can i get some help on this math question?

Mathematics

2 answers:

Lyrx [107]2 years ago

8 0

Answer:

on the first box is 2 on the last one its 18

Step-by-step explanation:

plz mark me brainliest

Helen [10]2 years ago

5 0

Answer:

Row 1: x=3; Row 3: y=18

Step-by-step explanation:

So to do this, look at where the line passes each of the x and y values it asks for within the graph.

In this question, x is the gallons of milk and y is the cost.

With the first part, it calls for the x value for when the y value is 6 dollars. With this, see where the line on the graph crosses 6 dollars. After doing this, you would see that the line passes over 6 dollars for when 2 gallons of milk are present. With this, write 3 under x.

With the other part, you do the same thing but now with the gallons of milk that are bought. So going up from where it says 6 gallons of milk on the graph, the line passes this over where it says $18. With this, write 18 under y.

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Dave has $15 to spend on an $8 dollar book and two birthday cards (c) for his friends. How much can he spend on each card if he

Alex_Xolod [135]

If Dave has 15 dollars and must spend 8 dollars of it on a book, then he will have 7 dollars left. If he then buys two of the same cards for his friends, the most he will be able to spend is half of 7 dollars for each of them, which will be 3 dollars and 50 cents.

7 0

2 years ago

To the nearest tenth, which is the BEST estimate for the volume of the given pyramid?

mixer [17]

Answer:

4.2 cubic inches

Step-by-step explanation:

Find the diagram attached

Volume of the rectangular pyramid = BH/3

B is the base area

H is the height of the pyramid

Given

Base area = 3.2in * 1.4in

Base area = 4.48sq. in

Height = 2.8in

Volume of the rectangular pyramid = 4.48*2.8/3

Volume of the rectangular pyramid = 12.544/3

Volume of the rectangular pyramid = 4.2 cubic inches

5 0

2 years ago

The amount of money spent on textbooks per year for students is approximately normal.

Ostrovityanka [42]

Answer:a

$336.04 < \mu < 443.96$

The margin of error will increase

The margin of error will decreases

The 99% confidence interval is $0.4107 < p < 0.4293$

Step-by-step explanation:

From the question we are told that

The sample size $n = 19$

The sample mean is $\= x = \$\ 390$

The standard deviation is $\sigma = \$ \ 120$

Given that the confidence level is 95% then the level of significance is mathematically represented as

$\alpha = 100 - 95$

$\alpha = 5 \%$

$\alpha = 0.05$

Next we obtain the critical value of $\frac{\alpha }{2}$ from the normal distribution table

$Z_{\frac{\alpha }{2} } = 1.96$

The margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{\sigma}{\sqrt{n} }$

=> $E = 1.96 * \frac{120}{\sqrt{19} }$

=> $E = 53.96$

The 95% confidence interval is

$\= x - E < \mu < \= x + E$

=> $390 - 53.96 < \mu < 390 - 53.96$

=> $336.04 < \mu < 443.96$

When the confidence level increases the $Z_{\frac{\alpha }{2} }$ also increases which increases the margin of error hence the confidence level becomes wider

Generally the sample size mathematically varies with margin of error as follows

$n \ \ \alpha \ \ \frac{1}{E^2 }$

So if the sample size increases the margin of error decrease

The sample proportion is mathematically represented as

$\r p = \frac{210}{500}$

$\r p = 0.42$

Given that the confidence level is 0.99 the level of significance is $\alpha = 0.01$

The critical value of $\frac{\alpha }{2}$ from the normal distribution table is

$Z_{\frac{\alpha }{2} } = 2.58$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} }* \sqrt{ \frac{\r p (1- \r p )}{n} }$

=> $E = 0.42 * \sqrt{ \frac{0.42 (1- 0.42 )}{ 500} }$

=> $E = 0.0093$

The 99% confidence interval is

$\r p - E < p < \r p + E$

$0.42 - 0.0093 < p < 0.42 + 0.0093$

$0.4107 < p < 0.4293$

4 0

3 years ago

Help, Please! I really need this done right Carlos is analyzing the results of an experiment on two groups of mice in which he c

Allushta [10]

Given:
difference in the mean weight gain is 0.60 grams
standard deviation of the difference in sample mean is 0.305

68% confidence interval for the population mean difference is a) 0.305

0.60 <u>+</u> 1 * 0.305
0.60 + 0.305 = 0.905
0.60 - 0.305 = 0.295

95% confidence interval for the population mean difference is c) 0.61

0.60 <u>+</u> 2 * 0.305
0.60 + 0.61 = 1.21
0.60 - 0.61 = -0.01

7 0

3 years ago

Can someone please help with 6 and 7? Thank you!

storchak [24]

Answer:

H and b

Step-by-step explanation:

4 0

3 years ago