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Reil [10]
3 years ago
5

Luke earned $20 shoveling driveways. He put 10% in his savings account and spent $9.50 on a game. How much money does he have le

Mathematics
1 answer:
Damm [24]3 years ago
8 0

Answer:

He has 50 cents left

Step-by-step explanation:

All you have to do is subtract 10 from 20 which is 10, then subtract $9.50 from 10 which only leaves us with 50 cents

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Which equation best models the fine schedule for overdue books? , where x is the cost in cents for a book that is y days overdue
earnstyle [38]

x is the independent variable, and in this scenario, the independent variable is the number of days overdue. So the best equation would be where x is the number of days overdue, and y is the cost in cents.


Example equation:



x = number of days overdue

y = cost in cents

z = total price

z = yx

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3 years ago
In the diagram below, AB is parallel to CD. What is the value of X?
Ivahew [28]
The answer would have to be 60
8 0
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Find The Solution Set Of The Following
Sunny_sXe [5.5K]

Answer:

what set can you show a picture?

Step-by-step explanation:

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3 years ago
two numbered 1 to 6 dice are thrown together and their scores are added. the probability that the sum will be 4 is?​
natulia [17]

Answer:

Pr = \frac{3}{36}

Step-by-step explanation:

Given

2 number die

Required

P(Sum = 4)

The sample space of 2 die is:

S = \{(1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6), (2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)

(3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6), (4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)

(5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6), (6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)

n(S)= 36

The pairs that adds up to 4 are:

Sum(4) = \{(1,3), (2,2),(3,1)\}

n(Sum)  =3

So, the probability is:

Pr = \frac{n(Sum)}{n(S)}

Pr = \frac{3}{36}

5 0
3 years ago
Otto invests $1,000 at age 20. Otto wants theinvestment to be worth $4,000 by age 30. Ifinterest is compounded continuously, wha
AveGali [126]
r\approx0.139

1) Since this is a Continuously Compounded operation in a 10 yrs period, then we can write out the following equation:

\begin{gathered} A=Pe^{rt} \\  \end{gathered}

2) Plugging into the equation the given data and since Otto is 20 yrs old and he plans to get $4,000 in ten years, we can write out:

\begin{gathered} 4000=1000e^{\mleft\{10r\mright\}} \\ \frac{4000}{1000}=\frac{1000e^{10r}}{1000} \\ 4=e^{10r} \\ \ln (4)=\ln (e)^{10r} \\ 10r=\ln (4) \\ r=\frac{\ln (4)}{10} \\ r=0.1386 \end{gathered}

3) Thus the rate Otto needs is

r=0.1386\approx0.139

Note that since the 0.1386 the six here is greater than 5 then we can round up to the next thousandth, in this case: 0.139. For the 0.1386 is closer to 0.139 (0.004) than to 0.138 (0.006).

Or 13.9%

8 0
1 year ago
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