Answer:
5
Step-by-step explanation:
Answer:
The proportion of students whose height are lower than Darnell's height is 71.57%
Step-by-step explanation:
The complete question is:
A set of middle school student heights are normally distributed with a mean of 150 centimeters and a standard deviation of 20 centimeters. Darnel is a middle school student with a height of 161.4cm.
What proportion of proportion of students height are lower than Darnell's height.
Answer:
We first calculate the z-score corresponding to Darnell's height using:

We substitute x=161.4 ,
, and
to get:

From the normal distribution table, we read 0.5 under 7.
The corresponding area is 0.7157
Therefore the proportion of students whose height are lower than Darnell's height is 71.57%
Answer:
65.4°
Step-by-step explanation:
According to question
The equation is
Cos(x)=5/12
x=acos(5/12)
x=65.4°
<u>Answer:</u>
The coordinates of endpoint V is (7,-27)
<u>Solution:</u>
Given that the midpoint of line segment UV is (5,-11) And U is (3,5).
To find the coordinates of V.
The formula for mid-point of a line segment is as follows,
Midpoint of UV is
, 
As per the formula,
=5,
=-11
Here 
Substituting the value of
we get,
=5



Substituting the value of
we get,
=-11



So, the coordinates of V is (7,-27)