Answer:
<h3>
- 14</h3>
Step-by-step explanation:
{x - some integer}
2x - the first even integer
2x+2 - the second consecutive even integer
2x+4 - the third consecutive even integer (the largest)
2x + 2x+2 + 2x+4 - the sum of three consecutive even integers
2x + 2x+2 + 2x+4 = -48
6x + 6 = -48
÷3 ÷3
2x + 2 = -16
+2 +2
2x+4 = -14
Answer: a. 0.61
b. 0.37
c. 0.63
Step-by-step explanation:
From the question,
P(A) = 0.39 and P(B) = 0.24
P(success) + P( failure) = 1
A) What is the probability that the component does not fail the test?
Since A is the event that the component fails a particular test, the probability that the component does not fail the test will be P(success). This will be:
= 1 - P(A)
= 1 - 0.39
= 0.61
B) What is the probability that a component works perfectly well (i.e., neither displays strain nor fails the test)?
This will be the probability that the component does not fail the test minus the event that the component displays strain but does not actually fail. This will be:
= [1 - P(A)] - P(B)
= 0.61 - 0.24
= 0.37
C) What is the probability that the component either fails or shows strain in the test?
This will simply be:
= 1 - P(probability that a component works perfectly well)
= 1 - 0.37
= 0.63
THE PROBABILITY IS likely to be one half half of the slice of the pizza
Answer:
f(x) | 5 | - 1 | - 3 | - 1 | 5 |
Step-by-step explanation:
So first you'll say "-2" into function
Replace x with negative 2
f(x) =2(-2) ^2 - 3
8 - 3 = 5
Secondly place "- 1" into function
Replace x with negative 1
f(x) = 2(-1)^2 - 3
2 - 3 = - 1
Thirdly place "0" into function
Replace x with 0
f(x) = 2(0)^2-3
0 - 3 = - 3
Then place "1" into function
Replace x with 1
f(x) = 2(1)^2 - 3
2 - 3 = - 1
Lastly place "2" into function
Replace x with 2
f(x) = 2(2)^2 - 3
8 - 3 = 5
{ hope this helps}
