Answer:
Area of the circle = 
π m² or 132.25 π m²
Step-by-step explanation:
To find the area, we will follow the steps below.
First write down the formular for the circumference of a circle, then use the formula to find the radius of the circle after which you can now find the area of the circle.
That is;
C = 2πr
where c is the circumference of the circle and r is the radius of the circle
From the question given, circumference C = 23π
23π = 2π r
Divide both-side of the equation by 2π
23π/2π = 2πr/2π
23/2 = r
radius = 
m
Formula for calculating the area of a circle is given by;
A = πr²
where A= area of the circle and r is the radius of the circle
A = π ( )²
A = π m² or 132.25 π m²
Area of the circle = π m² or 132.25 π m²
Answer:
Overall answer: 10 1/9 - 1 5/18x (Most simplified answer)
Step-by-step explanation:
First you have to do all the Distributive property which the answer would be:
2 1/2 - 1/2x + 3 1/9 + 8/9x + 1/6x - 5/18x + 2 14/18 + 1 13/18
Then you have to find the common demoninator which would be 18
After that you have to put them in the correct order since there is two different terms which would be:
2 9/18 + 3 2/18 + 2 14/18 + 1 13/18 - 9/18x + 16/18x + 3/18x - 5/18x
After that you solve the problem which in the end after solving both terms it ends up as..:
10 2/18 - 1 5/18x
and I think that is as simplified as you can go term wise.
I hope this helps and I hope I didn't make a mistake :D
Answer:
2. y = x + 16; 0.21y = 0.27x + 2.88
Step-by-step explanation:
You have two conditions:
- Volume of 18 % + volume of 27 % = volume of 21 %
- Mass of acid in 18 % + mass of acid in 27% = mass of acid in 21 %
For the first condition,
16 + x = y Transpose
(1) y = x + 16
=====
For the second condition
V₁c₁ + V₂c₂ = V₃c₃
16×0.18 + 0.27x = 0.21y
2.88 + 0.27x = 0.21y Transpose
(2) 0.21y = 0.27x + 2.88
The system of equations is y = x + 16; 0.21y = 0.27x + 2.88
Answer:
Step-by-step explanation:
Answer:
Step-by-step explanation:
Multiplication is Commutative. the term can be multiplied in either order. the product will be the same as the previous product.
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