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Semenov [28]
2 years ago
7

Suppose triangle ABC is reflected over the x-axis. If the distance between point A and A’ is 14, what is the distance between th

e x-axis and A’.
1. 7

2. -7

3. 3.5

4. There is not enough information given.
Mathematics
1 answer:
andreyandreev [35.5K]2 years ago
7 0

Given:

The triangle ABC is reflected over the x-axis.

The distance between point A and A’ is 14.

To find:

The distance between the x-axis and A’.

Solution:

If a figure is reflected across the x-axis then the corresponding parts are mirror image of each other about the x-axis.

It means the distance between A and x-axis is same as the distance between x-axis and A'.

The distance between point A and A’ is 14.

Let d be the distance between the x-axis and A’. Then,

d+d=14

2d=14

d=\dfrac{14}{2}

d=7

Therefore, the correct option is 1.

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Answer:

29

Step-by-step explanation:

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\frac{0.11x}{0.11} =\frac{3.19}{0.11}

Divide:

3.19÷0.11=29

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3 0
2 years ago
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Masja [62]
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3 years ago
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jek_recluse [69]

Answer: 62.8cm^2

Step-by-step explanation:

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where π is a constant, given as 3.14; h is the height, given as 3cm and r is radius, given as 2cm.

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I hope this helps

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Lady_Fox [76]

Answer:

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1 year ago
Eva is at a sushi restaurant. She ordered 2 pieces of squid for a total of $3.50, 1 piece of eel for $3.25, 3 pieces of tuna for
mixas84 [53]

Answer:

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Just make each sushi piece into an equation, then solve it.

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6 0
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