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HACTEHA [7]
3 years ago
7

Starting with the number 3, build a sequence of 5 numbers.

Mathematics
1 answer:
just olya [345]3 years ago
8 0

Answer:

3, 6, 9, 12, 15

adding 3 each time

or

3, 9, 27, 81, 243

multiplying by 3 each time

Step-by-step explanation:

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VOLLEBALL.Pick one volleyball skill and cover the most important content for learning that skill.
Cerrena [4.2K]

Answer:

The six basic volleyball skills are passing, setting, spiking, blocking, digging, and serving. Passing is often thought of as the most important skill in volleyball. If you can't pass the serve, then you won't ever put your team in a position to score a point. The importance of serving is often undervalued.

Step-by-step explanation:

hope this helps...

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6 0
3 years ago
The mean cost of a five pound bag of shrimp is 50 dollars with a variance of 64. If a sample of 43 bags of shrimp is randomly se
anyanavicka [17]

Answer:

0.4122 = 41.22% probability that the sample mean would differ from the true mean by greater than 1 dollar

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation(which is the square root of the variance) \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 50, \sigma = \sqrt{64} = 8, n = 43, s = \frac{8}{\sqrt{43}} = 1.22

What is the probability that the sample mean would differ from the true mean by greater than 1 dollar?

Either it differs by 1 dollar or less, or it differs by more than one dollar. The sum of the probabilities of these events is decimal 1.

Probability it differs by 1 dollar or less:

pvalue of Z when X = 50+1 = 51 subtracted by the pvalue of Z when X = 50 - 1 = 49.

X = 51

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{51-50}{1.22}

Z = 0.82

Z = 0.82 has a pvalue of 0.7939

X = 49

Z = \frac{X - \mu}{s}

Z = \frac{49-50}{1.22}

Z = -0.82

Z = -0.82 has a pvalue of 0.2061

0.7939 - 0.2061 = 0.5878

Probability it differs by more than 1 dollar:

p + 0.5878 = 1

p = 0.4122

0.4122 = 41.22% probability that the sample mean would differ from the true mean by greater than 1 dollar

4 0
3 years ago
Find the minimum and maximum possible areas of a rectangle measuring 6 km by 11 km.
defon
Area of rectangle=length * breadth
=6*11=66kmOR,6000m*11000m=66000000m
4 0
3 years ago
Solve for u.<br> 3x u = 12
koban [17]
U=4 because 3 x 4 is equal to 12
7 0
3 years ago
Read 2 more answers
I need help with this now pls!!
zubka84 [21]

Answer:

first box 9.6 2nd box 7.2 third box 12

Step-by-step explanation:

9.6 is the missing height 12 is the hypotenuse is always last

6 0
2 years ago
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