Question

Find the area of ABCD

Answer 1

Answer:

Applying Heron's Formula

$s=\frac{2.89+4.3+6.81}{2}$

$s_1=7$

$A_1=\sqrt{7(7-2.89)(7-4.3)(7-6.81)}$

$A_1=10.56$

Now, $s_2=\frac{6.81+8.59+7.58}{2}$

$s_2=11.49$

$A_2=\sqrt{11.49(11.49-6.81)(11.49-8.59)(11.49-7.59)}$

$A_2=24.69$

Total Area:

$10.56+24.69$

$=35.25$

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