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FinnZ [79.3K]
1 year ago
14

he length of a rectangle is 5 feet longer than it is wide. If each side is increased 5 feet, then the area is multiplied by 4. W

hat was the size of the original rectangle?
Mathematics
1 answer:
Effectus [21]1 year ago
5 0

Answer:

Length = 8\frac{1}{3}

width = 3\frac{1}{3}

Step-by-step explanation:

let width be equal to x and length be equal to x+5.

area = x(x+5)

if we add 5 to each side, area becomes 4 times bigger.

(x+5)(x+10)

set them equal to each other.

4(x(x+5)=(x+5)(x+10)

solve for x.

x=\frac{10}{3};x=-5

since you know you can't have a side that has negative values, it has to be x=\frac{10}{3}

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Solve for x <br> y=-1/2x=3
ANEK [815]

Answer:

-6

Step-by-step explanation:

x=-6

5 0
3 years ago
In the figure, AngleRQS Is-congruent-to AngleQLK. 3 lines are shown. Lines S P and K N are parallel. Line R M intersects line S
stepan [7]

Answer:

x=108

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

m∠RQS≅m∠QLK -----> by corresponding angles

m∠KLM+m∠QLK=180° -----> by supplementary angles (consecutive interior angles)

we have that

m∠RQS=x° ----> given problem

so

m∠QLX=x°

m∠KLM=(x-36)° ----> given problem

substitute

(x-36)\°+x\°=180\°\\2x=180+36\\2x=216\\x=108

3 0
3 years ago
Read 2 more answers
Ocean Bike Tours wants to provide bandanas for each person. The cost of the bandanas is each person. The cost of the bandana is
mixas84 [53]

Answer:

$145.50

Step-by-step explanation:

C = 45.50 + 2n

45.50 + 2X 100 = $145.50

7 0
3 years ago
Will mark brainliest help!
kakasveta [241]

Answer:

52.5

Step-by-step explanation:

Since ED ≈ AD, ∆AED is a isosceles triangle where <EAD and <AED has same angle measurement

Now, m<B = 105°, since ABCD is a parallelogram, <B = <D

so, m<ADC = 105° so, m<ADE = 180°-105° = 75°

Now, m<EAD+m<AED+m<ADE = 180°

or, m<AED+m<AED+m<ADE = 180°

or, x+x+75°=180°

or, 2x=180+75°

or, 2x=105°

or, x=52.5°

3 0
3 years ago
How did he get this 1/2i ? I dont remember studying this definition in calc 1 neither calc 2!
Hitman42 [59]
The i in the denominator is missing in the second expression. It should be

\sin at=\dfrac{e^{iat}-e^{-iat}}{2i}

This follows from

e^{iat}=\cos at+i\sin at
e^{-iat}=\cos at-i\sin at
\implies e^{iat}-e^{-iat}=2i\sin at
\implies \sin at=\dfrac{e^{iat}-e^{-iat}}{2i}
8 0
4 years ago
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