What are the zeroes of the function nf(x) = x2 + 2x - 35?

Mathematics

2 answers:

tiny-mole [99]3 years ago

5 0

Answer:

x = - 7, x = 5

Step-by-step explanation:

To find the zeros, let f(x) = 0 , that is

x² + 2x - 35 = 0 ← in standard form

(x + 7)(x - 5) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 7 = 0 ⇒ x = - 7

x - 5 = 0 ⇒ x = 5

Ann [662]3 years ago

5 0

$\huge{ \mathfrak{ \underline{ Answer } \: ✓ }}$

${x}^{2} +2 x - 35$

${x}^{2} + 7x - 5x - 35$

$x(x + 7) - 5(x + 7)$

$(x + 7)(x - 5)$

> Equating with zero

Case - 1

x + 7 = 0
x = -7

Case - 2

x - 5 = 0
x = 5

The required Zeroes are :

$\huge\boxed{5 \: \: \: and -7}$

_____________________________

$\mathrm{ \#TeeNForeveR}$

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