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joja [24]
3 years ago
14

Booker has 4 packs of trading cards. There are 12 cards in each pack. is this divison

Mathematics
2 answers:
Lostsunrise [7]3 years ago
6 0
The answer is 48 12 times 4 is 48
Murljashka [212]3 years ago
3 0
<span>Booker has 4 packs of trading cards. There are 12 cards in each pack.
is this divison.
Yes! It is!

</span>
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Order of operations- what does each letter represent? P, D, M, A, S
allsm [11]

P, D, M, A, S.

P: Parenthesis

D: Divide

M: Multiply

A: Add

S: Subtract

5 0
3 years ago
Read 2 more answers
Please help asap!!!!
bearhunter [10]

Answer:

(using substitution to solve the problem)

x=y-3

2x+y=12

2(y-3)+y=12

2y-6+y=12

3y=18

y=6

y=6

x=6-3

= (3, 6)

Step-by-step explanation:

using substitution, substitute the x in the second equation to y-3, to find the value of y. after that distribute the 2 into the parenthesis and collect like terms. once you simplify, you have the value of y, so substitute the value of y into the first equation to find x. once you have both values put them in the ordered pair form and you're done.

i hope this helps :)

3 0
3 years ago
Ella can read 2 pages in 3<br> minutes. How long will it take her<br> to read 45 pages ?
hammer [34]

Answer:

15 minutes

Step-by-step explanation:

2 pages = 3 minutes

45 pages = 3x minutes

45 / 3 = 15

6 0
3 years ago
14. Higher Order Thinking: Lauren can drive her car 320 miles on 10 gallons of gasoline. Melissa can drive her car 280 miles on
Jlenok [28]

Answer:

d

Step-by-step explanation:

5 0
3 years ago
Find the inverse of the given function.
Bogdan [553]

Answer:

The inverse is

<h2>y =\sqrt{\frac{(\frac{x-3}{3}) ^{2}+5}{2}}</h2>

Step-by-step explanation:

y=3\sqrt{2x^{2} -5} + 3

To find the inverse of the function interchange the terms that's x becomes y and y becomes x

We have

x=3\sqrt{2y^{2}-5 }+3

Now solve for y

<u>Move 3 to the other side of the equation</u>

3\sqrt{2y^{2}-5 } = x-3

Divide both sides by 3

We have

\sqrt{2y^{2}-5 } =\frac{x-3}{3}

<u>square both sides of the equation to remove the square root</u>

That's

2y^{2}-5  = (\frac{x-3}{3}) ^{2}

<u>Move 5 to the other side of the equation</u>

2y^{2} = (\frac{x-3}{3}) ^{2}+5

<u>Divide both sides by 2</u>

We have

y^{2} = \frac{(\frac{x-3}{3}) ^{2}+5}{2}

<u>Find the square root of both sides</u>

We have the final answer as

y =\sqrt{\frac{(\frac{x-3}{3}) ^{2}+5}{2}}

Hope this helps you

7 0
4 years ago
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