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2 years ago

What is the length of BC

Mathematics

1 answer:

levacccp [35]2 years ago

8 0

Answer:
Re-submit ur question sweet heart

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Help me pls this is due tomorrow at 8:00 am

bixtya [17]

Answer:

it would be what they said

Step-by-step explanation:

so sorry i need 50 pts

6 0

2 years ago

Read 2 more answers

A normal distribution has a mean of 101 and a standard deviation of 3.4. What is the z-score of 105? Enter your answer, rounded

oee [108]

Answer:

Z-score = 1.18

Step-by-step explanation:

The z-score measures how many standard deviations from the mean a data is

Therefore the z score is the quotient between the difference between a value and the mean and the standard deviation

$Z =\frac{X-\mu}{\sigma}$

Where

μ is the mean, x is a data of the population and $\sigma$ is the standard deviation

In this case

$\mu =101\\\\\sigma = 3.4\\\\X = 105$

Then the z-score is

$Z = \frac{105-101}{3.4}\\\\Z = 1.18$

4 0

3 years ago

Use the given transformation x=4u, y=3v to evaluate the integral. ∬r4x2 da, where r is the region bounded by the ellipse x216 y2

exis [7]

The Jacobian for this transformation is

$J = \begin{bmatrix} x_u & x_v \\ y_u & y_v \end{bmatrix} = \begin{bmatrix} 4 & 0 \\ 0 & 3 \end{bmatrix}$

with determinant $|J| = 12$ , hence the area element becomes

$dA = dx\,dy = 12 \, du\,dv$

Then the integral becomes

$\displaystyle \iint_{R'} 4x^2 \, dA = 768 \iint_R u^2 \, du \, dv$

where $R'$ is the unit circle,

$\dfrac{x^2}{16} + \dfrac{y^2}9 = \dfrac{(4u^2)}{16} + \dfrac{(3v)^2}9 = u^2 + v^2 = 1$

so that

$\displaystyle 768 \iint_R u^2 \, du \, dv = 768 \int_{-1}^1 \int_{-\sqrt{1-v^2}}^{\sqrt{1-v^2}} u^2 \, du \, dv$

Now you could evaluate the integral as-is, but it's really much easier to do if we convert to polar coordinates.

$\begin{cases} u = r\cos(\theta) \\ v = r\sin(\theta) \\ u^2+v^2 = r^2\\ du\,dv = r\,dr\,d\theta\end{cases}$

Then

$\displaystyle 768 \int_{-1}^1 \int_{-\sqrt{1-v^2}}^{\sqrt{1-v^2}} u^2\,du\,dv = 768 \int_0^{2\pi} \int_0^1 (r\cos(\theta))^2 r\,dr\,d\theta \\\\ ~~~~~~~~~~~~ = 768 \left(\int_0^{2\pi} \cos^2(\theta)\,d\theta\right) \left(\int_0^1 r^3\,dr\right) = \boxed{192\pi}$

3 0

1 year ago

Given the trinomial 2x2 − 5x + 3, what is the value of the Discriminant and what can be said about the solutions.

valina [46]

The formula to finding a discriminant would be b^2-4ac, the b value of this trinomial being -5, the a value being 2, the c value being 3. Then, you plug the values in the equation and solve: (-5)^2-4(2)(3)
This would simplify to 1, meaning there are two solutions since the discriminant value is positive. If it is 0, there is one solution, if it is negative, then there are no real solutions.

4 0

3 years ago

Solve for F: 5/9 (F-32)

konstantin123 [22]

The answer is -31 2/5<span />

8 0

3 years ago