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exis [7]
3 years ago
7

3. Make F the subject of the formulaH-2FLW3F​

Mathematics
1 answer:
lord [1]3 years ago
5 0

Answer:

Step-by-step explanation:

Ur still up

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4 years ago
PLEASE HELP ME WITH THIS THANKS
kotykmax [81]

Answer:

SA = 1244.64 square centimeters

Step-by-step explanation:

From the attached figure

The formula of the surface area of the prism is SA = 2B + PH, where

  • B is the area of its base
  • P is the perimeter of its base
  • H is the distance between its bases

The base of the prism is a regular hexagon with side 8 cm

If you join each vertex of the hexagon with its center you will form 6 congruent triangles with base 8 cm and height 6.93 cm

The area of the hexagon = 6 × area of a triangle

∵ The base of the triangle = 8 cm

∵ Its height = 6.93 cm

- The formula of the area of a triangle is A = \frac{1}{2} × base × height

∴ Area of the triangle = \frac{1}{2} × 8 × 6.93 = 27.72 cm²

- Lets find the area of the hexagon

∴ The area of the hexagon = 6 × 27 .72 = 166.32 cm²

∴ B = 166.32 cm²

The formula of the perimeter of the regular hexagon is P = 6 × s, where s is the length of its side

∵ The side of the hexagon is 8 cm

∴ P = 6 × 8

∴ P = 48 cm

∵ The distance between the two bases is 19 cm

∴ H = 19 cm

Substitute the values of B, P and H in the formula of the surface area above

∵ SA = 2(166.32) + (48)(19)

∴ SA = 332.64 + 912

∴ SA = 1244.64 square centimeters

7 0
3 years ago
What is 2/3 divided by 4 in the Simplest form?
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Answer:

2/3 divided by 4 = .16

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Find the minimum and maximum possible areas of a rectangle measuring 6 km by 11 km.
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Assuming your numbers are rounded to the nearest km, the minimum area will be ...
  (5.5 km)·(10.5 km) = 57.75 km² . . . minimum

And the maximum area will be ...
  (6.5 km)·(11.5 km) = 74.75 km² . . . maximum

_____
When a number is rounded to 6 km as the nearest km, its value may actually be anywhere in the range 6 km ± 0.5 km. If you really want to get technical about it, the ranges of possible dimensions are [5.5, 6.5) km and [10.5, 11.5) km, and the range of possible areas is [57.75, 74.75) km².
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