Question

Given right triangle ABC with altitude BD drawn to hypotenuse AC. If AD = 4 and dc =2 what is the length of ad

Answer 1

Question is slightly wrong .We have to find BD

• AD=4
• CD=2

we know

$\boxed{\sf BD^2=AD\times DC}$

$\\ \qquad\quad\sf{:}\twoheadrightarrow BD^2=4\times 2$

$\\ \qquad\quad\sf{:}\twoheadrightarrow BD^2=8$

$\\ \qquad\quad\sf{:}\twoheadrightarrow BD=\sqrt{8}$

$\\ \qquad\quad\sf{:}\twoheadrightarrow BD=2√2$

$\\ \qquad\quad\sf{:}\twoheadrightarrow BD=2(1.4)$

$\\ \qquad\quad\sf{:}\twoheadrightarrow BD=2.8$