6. If sin 0 < 0 and cot 0 < 0, which quadrant(s) could the terminal side of 0 lie?
1 answer:
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Answer:
Step 2
Step-by-step explanation:
The quadratic formula is given by
Our equation is y = 2x²-x-6
So here our a = 2, b = -1, and c = -6
We can now plug these numbers into our formula
Step 2 is incorrect because it states that "x equals the negative of negative 1 plus or minus the square root of negative one plus forty-eight all over two times 2."
The correct statement would be "x equals the negative of negative 1 plus or minus the square root of positive one plus forty-eight all over two times 2.", because the square of a negative is positive, resulting in a positive one.
Since this step is incorrect, the steps after are also incorrect, but Harry went wrong at Step 2