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Brilliant_brown [7]

3 years ago

13

Please help me ASAP!!

1 answer:

Degger [83]3 years ago

5 0

Answer:

30.9 cm^2

Step-by-step explanation:

A=(3*2.6)/2+3*(3*6)/2=3.9+27=30.9 cm^2

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I need help plz !!!!!!!

morpeh [17]

0: 3000

5: 500

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5 0

2 years ago

The outside temperature at 6:00 was 75º F. The temperature dropped 0.8ºF for the next 4 hours.What was the outside temperature a

otez555 [7]

Answer:

71.8° F

Step-by-step explanation:

Given 75° and 4 times 0.8° drop = 3.2°, so the temperature is 75° - 3.2°

= 71.8° F

4 0

3 years ago

Write as a single logarithm 3-1/2(log6+log3-3log2)

faust18 [17]

$3-\dfrac{1}{2}\left(\log6+\log3-3\log2\right)=\\
\log10^3-\dfrac{1}{2}\left(\log\left(6\cdot3\right)-\log2^3\right)=\\
\log1000-\dfrac{1}{2}\left(\log18-\log8\right)=\\
\log1000-\dfrac{1}{2}\left(\log\dfrac{18}{8}\right)=\\
\log1000-\dfrac{1}{2}\left(\log\dfrac{9}{4}\right)=\\
\log1000-\log\left(\dfrac{9}{4}\right)^{\dfrac{1}{2}}=\\
\log1000-\log\sqrt{\dfrac{9}{4}}=\\
\log1000-\log\dfrac{3}{2}=\\
\log\dfrac{1000}{\frac{3}{2}}=\\
\log\left(1000\cdot\dfrac{2}{3}\right)=\\
\log\dfrac{2000}{3}$

6 0

2 years ago

Read 2 more answers

Two cars are traveling towards a hotel on the same road. From the edge of the hotel, 600 feet high, Spiderman sits on the roofto

d1i1m1o1n [39]

Answer:

The distance between two cars is 110.64 feet.

Step-by-step explanation:

Angle of depression is defined as an angle between the line of sight and the horizontal.

Remember in a right angled triangle, the angle of depression is always same as the angle of elevation.

If $\theta$ be the angle of depression then,

$tan\theta=\frac{opposite}{adjacent}$

Given that,

Two car are travelling toward a hotel on the same road.

The height of the given building is 600 feet.

For the first car:

The angle of depression = The angle of elevation = 52°

Let the horizontal distance between the building and the car be x.

Here, $\theta =52 ^\circ$ , opposite = 600 feet, adjacent = x

$tan 52^\circ=\frac{600}{x}$

$\Rightarrow x=\frac{600}{tan 52^\circ}$

$\Rightarrow x\approx 468.77$ feet

For the second car:

The angle of depression = The angle of elevation = 46°

Let the horizontal distance between the building and the car be y.

Here, $\theta =46 ^\circ$ , opposite = 600 feet, adjacent = y

$tan 46^\circ=\frac{600}{y}$

$\Rightarrow y=\frac{600}{tan 46^\circ}$

$\Rightarrow x\approx 579.41$ feet

The distance between two cars is

= The distance of the second car from the building - The distance of the first car from the building

=(579.41-468.77) feet

=110.64 feet.

3 0

3 years ago

Solve for x: x/6 - 2 = 13

Mumz [18]

X=90
Hope this helps!

3 0

2 years ago