If a line has a slope of 4 and contains the point (-2, 5), what is its equation in point-slope form?

Mathematics

1 answer:

Sveta_85 [38]3 years ago

8 0

Answer:

The equation of the line is y = 4x + 13

Step-by-step explanation:

In this question, we want to write the equation of the line using the point slope form.

Mathematically, the point slope form can be represented as;

(y-y1) = m(x - x1)

where x1 = -2 , y1 = 5 and m which is the slope is 4

Plugging these values into the equation, we have;

(y-5) = 4(x - (-2))

y-5 = 4(x + 2)

y -5 = 4x + 8

y = 4x + 8 + 5

y = 4x + 13

You might be interested in

Marley runs 5 yards down the track from point A to point B, and then stops and runs

julia-pushkina [17]

Answer:

$\sqrt{61}$ =AC or 7.8102=AC

Step-by-step explanation:

If we connect a line from point A to point C we create a triangle, and we can use pythagorean theorem to find this distance. So the line from point A to point C will be our hypotenuse and the other two distances will be out side lengths.

$5^{2}+6^{2}=AC^{2}$

25+36= $AC^{2}$

61= $AC^{2}$

$\sqrt{61}$ =AC or 7.8102=AC

3 0

3 years ago

PLEASEEE HELP ME WITH THIS!!!

andreev551 [17]

Answer:

m∠H = 10°

Step-by-step explanation:

ΔFGH is an isosceles triangle. I made a diagram, so m∠F ≅ m∠H by B.A.T(base angle theorem). This is because an isosceles triangle have to congruent sides and angles.

Diagram is attached:

-Chetan K