The organism would not have to find a partner in order to reproduce.
Answer:
1500
Explanation:
Let's assume that the allele for yellow seed color is "Y" and the allele for green seed color is "y". Genotype of pure breeding yellow seeded plant would be "YY" and that of the green seeded plant would be "yy". A cross between YY and yy gives all heterozygous yellow seeded plants (Yy) in F1 progeny. Self pollination of two F1 plants (Yy x Yy) obtains F2 generation in 3 yellow: 1 green ratio.
The total population size of F2 generation = 2000
The proportion of yellow seeded plants in F2 generation = 3/4 (since the F2 phenotype ratio is given 3 yellow: 1 green)
Therefore, total number of yellow seeded plants in F2 progeny = 3/4 x 2000= 1500
<u>Answer</u>:- <em>Option 3 </em>(desert), <em>Option 4</em> (tundra) and <em>Option 5</em> (grassland).
<u>Explanation</u>:-
The amount of rainfall varies in different biomes:-
1. Tropical rain forests - The annual rainfall in these forests falls in the range of <em>125 to 660 cm</em> which varies according to the seasons.
2. Temperate rain forest - The annual rainfall in these forests can range from <em>200 cm to 350 cm</em> depending on the region where they are found. The annual rainfall is higher in warmer regions .
3. Desert - As the name suggests, the desert areas do not get enough rainfall. The annual rainfall in a desert is less than <em>25 cm</em>.
4. Tundra - It is a biome which is found in relatively cooler climates and the amount of rainfall is very less these regions. The annual rainfall in tundra biomes is less than <em>20 cm</em>.
5. Grassland - in these biomes, the rainfall is higher than the tundra and desert but is not as high as the rain forests and thus, grass is the dominant vegetation. The annual rainfall ranges from <em>60-90 cm</em>.
the chances of that happening are 8/52 which reduces to 2/13. So not very good