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vekshin1
3 years ago
12

PLEASE HELP ME PLEASE HELP ME PLEASE HELP ME PLEASE HELP ME PLEASE HELP ME

Mathematics
1 answer:
fredd [130]3 years ago
4 0
You answer would be -4,-5 because you got to look where there line cross
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The length of a rectangle is 4 m
dimulka [17.4K]

Answer:

Given :

The length of a rectangle is 4 cm more than its width

The area of the rectangle is 96 cm²

To Find :

Width of the rectangle.

Solution :

Let the length of the rectangle be x cm.

Let the breadth of the rectangle be y cm.

Case 1:

➣

➣  _____(1)

Case 2 :

We have the formula for area of the rectangle as follows :

Where,

l = length → x cm

b = breadth → y cm.

➣

➣

Substitute, x = 96/y in equation 1,

➣

➣

➣

➣

➣

Divide by minus sign,

➣

➣

➣

➣

➣

➣

➣

As per assumption, y = breadth of the rectangle.

•°• y = -12 is not acceptable.

Substitute, y = 8 in equation 1,

➣

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Step-by-step explanation:

6 0
2 years ago
Benifits of social media when reporting about gbv
frutty [35]

Step-by-step explanation:

Coordinate referrals and advocate with partner organizations supporting GBV survivors to provide confidential services to clients, in accordance with their wishes, GBV guiding principles and informed consent.

5 0
3 years ago
one and one-half dozen cookies take 2/3 of a cup of sugar. how much sugar is needed to make 90 cookies
sladkih [1.3K]
Approx. 3  1/3 cups. 1 1/2 dozen equals 18 cookies.  90/18=5 . Then you multiply 5 by .666(rep) and it equals =3.3333333(rep)  or approx. 3 1/3 cups of sugar.
6 0
3 years ago
Suppose that we will randomly select a sample of 106 measurements from a population having a mean equal to 19 and a standard dev
svet-max [94.6K]

Answer:

z =\frac{18.45-19}{\frac{7}{\sqrt{106}}}= -0.809

And if we use the normal standard distribution or excel we got:

P(z

Step-by-step explanation:

For this case we have the following info given:

\mu = 19 represent the mean

\sigma = 7 represent the standard deviation

n = 106 represent the sample size

The distribution for the sample size if we use the central limit theorem (n>30) is given by:

\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})

And for this case we want to find the following probability:

P(\bar X< 18.45)

And for this case we can use the z score formula given by:

z =\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And replacing we got:

z =\frac{18.45-19}{\frac{7}{\sqrt{106}}}= -0.809

And if we use the normal standard distribution or excel we got:

P(z

4 0
3 years ago
Can someone help me please ???????
Inessa [10]

Answer:

d=1

Step-by-step explanation:

Factor d^2 - 2d - 8 into (d-4)(d+2)

Move -2/d+2 onto the other side, changing it into 2/d+2.

\frac{-3d}{(d-4)(d+2)} +\frac{3}{d-4}+\frac{2}{d+2} = 0

Let the empty side equal zero.

Add 3/d-4 and 2/d+2

\frac{5d-2}{(d+2)(d-4)}

Then add that to -3d.

\frac{2d-2}{(d+2)(d+4)}

Multiply 0 by d+2 and d-4 to get 2d-2 by itself.

2d=2

d=1

I can't edit the equation, but it's d-4 althroughout the question. Sorry for being so slow.

6 0
3 years ago
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