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Nonamiya [84]
3 years ago
11

If you have consistently been exercising during the school year but then take the

Mathematics
1 answer:
Colt1911 [192]3 years ago
6 0

Answer:

Step-by-step explanation:

B

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Determine the value of x in each figure.
velikii [3]

Answer:

x=15is your answer

Step-by-step explanation:

8x=120 vertically opposite angle

x=120/8=15

3 0
3 years ago
Read 2 more answers
calculate the total potential energy in kj of an object whose mass is 20 kg when it is located 20 m below a datum level in a loc
Airida [17]

Answer:

The energy in object is 3.8 Kilo Joules.  

Step-by-step explanation:

We are given the following in the question:

Mass = 20 kg

Height,h = 20 m

g=9.5 m/s^2

Formula:

Potential energy  =

E = Mgh

Putting value we get,

E = 20(20)(9.5)\\E = 3800~J\\E = 3.8~KJ

Thus, the energy in object is 3.8 Kilo Joules.

5 0
3 years ago
If cos B is 4/5 what is sin a?​
Keith_Richards [23]

Answer:

sin(A+B)=sinAcosB+cosAsinB. Putting the values in. sin(A+B)=(4/5)(−3/5)+(3/5)(−4/5). sin(A+B)=−24/25.

8 0
3 years ago
Eight f subtract three f plus two plus five equals
Zolol [24]

Answer:

5f + 7

Step-by-step explanation:

8f-3f+2+5

8f-3f is 5f and 2 + 5 is 7

5f+7

6 0
3 years ago
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Write the functions by the graphs <br> F(x)=<br> G(x)=<br> H(x)=
Alborosie

Answer:

f(x) = |x|

g(x) = |x| - 2

h(x) = |x| + 3

Step-by-step explanation:

All the functions graphed represent the absolute value functions.

Since function g(x) passes through (0, 0) and (1, 1),

Let the equation of a line passing through these points is,

y = mx + b

Slope of the line passing through these points 'm' = \frac{\text{Rise}}{\text{Run}}=\frac{1-0}{1-0}

m = 1

y-intercept of the line 'b' = 0

Therefore, equation of the line will be,

y = x

And the function representing the two lines (both are the mirror images) joining at the origin will be,

f(x) = |x|

When the parent function is shifted 3 units up, the new function will be

h(x) = |x| + 3

When the parent function is shifted 2 units down,

g(x) = |x| - 2

8 0
3 years ago
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