If you have consistently been exercising during the school year but then take the

Sketch one cycle of the cosine function y= cos 2θ

Liula [17]

Based on function transformations, the graph of y= cos(2θ), is the same as the graph of <span>y= cos(θ), with a component B of 2, in which case, it means the period is the only thing that differs

well the period for this function will then be </span> $\bf \cfrac{2\pi }{B}\iff \cfrac{2\pi }{2}\implies \pi$

so, the graph of is, the same as y= cos(θ), just shrunk by half horizontally

7 0

3 years ago

Is x 12 or 15? Or none?

Usimov [2.4K]

The answer is 15 buddy!

7 0

3 years ago

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7.Find the lengths of the missing sides in the triangle. If your answer is not an integer, leave it in simplest radical form. Th

Fed [463]

Here a right angled triangle given. one angle with measure $45^o$ given. The three sides of the triangle given 4, x, y.

We have to find, the sides which is opposite, adjacent and hypotenuse here.

We know that the side opposite to right angle is always hypotenuse. So, hypotenuyse = y.

The side adjacent to the given angle $45^o$ is x. So, here adjacent = x.

The opposite side is opposite to the given angle. So, opposite = 4.

Now we will use SOHCAHTOA that is $sin(x) =\frac{Opposite}{Hypotenuse} , cos(x) =\frac{Adjacent}{Hypotenuse} , tan(x) =\frac{Opposite}{Adjacent}$ , where x is the angle given.

To get x, we will use tan. So we will get,

$tan(45^o) = \frac{4}{x}$

We know the value of $tan(45^o) = 1$ . By substituting the value we will get,

$1 =\frac{4}{x}$

To find x, we have to move x here to the left side by multiplying it to both sides. We will get,

$(1)(x) = (\frac{4}{x}) (x)$

$x = 4$

So we have got the value of x here.

Now to find y, we will use the trigonometric function sine.

$sin(45^o) =\frac{4}{y}$

we know the value of $sin(45^o) =\frac{\sqrt{2}}{2}$

By substituting the value we will get,

$\frac{\sqrt{2}}{2} = \frac{4}{y}$

By cross multiplying we will get,

$(\sqrt{2}) (y) = (4)(2)$

$\sqrt{2}y = 8$

We will get y by dividing both sides by $\sqrt{2}$ , we will get,

$\frac{\sqrt{2}y}{\sqrt{2}} =\frac{8}{\sqrt{2} }$

$y =\frac{8}{\sqrt{2} }$

Now we will rationalize the denominator by multiplying $\sqrt{2}$ to the top and bottom.

$y =\frac{8\sqrt{2}}{(\sqrt{2})(\sqrt{2})}$

$y =\frac{8\sqrt{2}}{2}$

$y = 4\sqrt{2}$

So we have got the required values of x and y.

8 0

3 years ago

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Help me please! which bisects the chord?

8_murik_8 [283]

Answer:

B. 3

Step-by-step explanation:

Since you are given that chord AB's length is 8 and is bisected by segment XC, that means segment BC's length is 4 and ∠XCB is a right angle. From there, we use Pythagorean Theorem to solve for length XC:

4² + b² = 5² (Or remember 3-4-5 makes a Pythagorean triple)

c = √(5²-4²)

c = 3

6 0

3 years ago

A frog is jumping onto a lily pad. Its height, h (in feet), is recorded at various seconds, t, in the

myrzilka [38]

Answer:

I don't know

Step-by-step explanation:

sorry

7 0

3 years ago