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Varvara68 [4.7K]
3 years ago
12

Find the volume for 2 different spheres by randomly choosing different radii.

Mathematics
1 answer:
grigory [225]3 years ago
6 0

Answer:

The volume of a sphere of radius r is:

S = (4/3)*pi*r^3

The volume of a cylinder of radius r and height h is:

C = pi*r^2*h

For this problem the height of the cylinders will be equal to the diameter of the spheres, which is equal to two times the radius.

First, let's use the radius: r = 2.

The volume of the sphere will be:

S = (4/3)*3.14*(2)^3 = 33.49

The volume of the cylinder, where h = 2*2 = 4, is:

C = 3.14*(2^2)*4 = 50.24

Now, let's choose the radius r = 3.

The volume of the sphere will be:

S = (4/3)*3.14*3^3 = 113.04

The volume of a cylinder with this radius and h = 3*2 = 6, is:

C = 3.14*(3^2)*6 = 169.56

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*******************************************************
(See attached formula)
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In doing so, you collect a random sample of 50 salespersons employed by his company, which is thought to be representative of sa
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Answer:

z=\frac{0.36 -0.45}{\sqrt{\frac{0.45(1-0.45)}{50}}}=-1.279  

p_v =P(z

And we can use the following code to find it  "=NORM.DIST(-1.279,0,1,TRUE)"

Step-by-step explanation:

Assuming this complete problem: "The CEO of a software company is committed to expanding the proportion of highly qualified women in the organization's staff of salespersons. He believes that the proportion of women in similar sales positions across the country is less than 45%. Hoping to find support for his belief, he directs you to test

H0: p .45 vs H1: p < .45.

In doing so, you collect a random sample of 50 salespersons employed by his company, which is thought to be representative of sales staffs of competing organizations in the industry. The collected random sample of size 50 showed that only 18 were women.

Compute the p-value associated with this test. Place your answer, rounded to 4 decimal places, in the blank. For example, 0.3456 would be a legitimate entry."

1) Data given and notation

n=50 represent the random sample taken

X=18 represent the number of women in the sample selected

\hat p=\frac{18}{50}=0.36 estimated proportion of women in the sample

p_o=0.45 is the value that we want to test

\alpha represent the significance level

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the proportion of women is less than 0.45:  

Null hypothesis:p\geq 0.45  

Alternative hypothesis:p < 0.45  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.36 -0.45}{\sqrt{\frac{0.45(1-0.45)}{50}}}=-1.279  

4) Statistical decision  

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The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(z

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