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3 years ago

Write the following linear equations in slope-intercept form:

Mathematics

2 answers:

Vika [28.1K]3 years ago

8 0

Answer:

1) y = 3x - 11

2) y = -2x - 10

3) y = 2x - 5

4) y = -4x + 20

marin [14]3 years ago

7 0

Answer:

1) y = 3x - 11

2) y = -2x - 10

3) y = 2x - 5

4) y = -4x + 20

Step-by-step explanation:

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Because weightlessness in outer space causes astronauts to lose bone mass, at the end of each month, an astronaut has two percen

vlabodo [156]

Answer:

There will be 88.6% of her bone mass remaining when she returns to earth.

Step-by-step explanation:

According to the problem, the astronaut will have 2% less bone mass than at the beginning of that month. So let's say $B_{0}$ is her original bone mass. In that case, her bone mass after the first month will be:

$B_{1}=B_{0}(0.98)$

on the second month, her bone mass will be:

$B_{2}=B_{1}(0.98)=B_{0}(0.98)(0.98)=B_{0}(0.98)^{2}$

on the third month, her bone mass will be:

$B_{3}=B_{2}(0.98)=B_{0}(0.98)(0.98)(098)=B_{0}(0.98)^{3}$

and so on, we can see a pattern here. The formula for her remaining bone mass can be generally written like this:

$B_{n}=B_{0}(0.98)^{n}$

where n is the number of months, so after 6 months, her remaining bone mass will be:

$B_{6}=B_{0}(0.98)^{6}=0.886B_{0}$

that 0.886 gives us the percentage as a decimal number. When turned into a percentage we get that:

There will be 88.6% of her bone mass remaining after 6 months.

7 0

3 years ago

Find the perimeter of rectangle BCEF. Round your answer to the nearest hundredth

777dan777 [17]

Answer:

The perimeter of the rectangle B C E F is 16.97 units

Step-by-step explanation:

* Lets explain how to solve the problem

- B C E F is a rectangle

- The perimeter of the rectangle is the sum of the length of its

four sides

- The coordinates of the vertices of the rectangle are:

B (0 , 3) , C (4 , -1) , E (2 , -3) , F (-2 , 1)

- To find the dimensions of the rectangle use the rule of distance

d = $\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

* Lets solve the problem

∵ $(BC)=\sqrt{(4-0)^{2}+(-1-3)^{2}}=\sqrt{16+16}=\sqrt{32}$

∵ $(CE)=\sqrt{(2-4)^{2}+(-3--1)^{2}}=\sqrt{4+4}=\sqrt{8}$

∵ $(FE)=\sqrt{(2--2)^{2}+(-3-1)^{2}}=\sqrt{16+16}=\sqrt{32}$

∵ $(BF)=\sqrt{(-2-0)^{2}+(1-3)^{2}}=\sqrt{4+4}=\sqrt{8}$

∵ The perimeter of the rectangle = BC + CE + FE + BF

∴ The perimeter = $\sqrt{32}+\sqrt{8}+\sqrt{32}+\sqrt{8}=16.97$

∴ The perimeter of the rectangle B C E F is 16.97 units

4 0

4 years ago

Round 11 580 to 3 significant figures

Dmitriy789 [7]

11,580 to 3 significant figures
Currently, the value has 5 significant figures ( inclusive of 0 )
next to 5, there is 8 and 8 > 5, so 5 rounds up
1.16 x 10⁴