4m+28=44
4m=44-28
4m=16
m=16/4
m=4
Answer:
A
Step-by-step explanation:
Answer:
Step-by-step explanation:
To find : Acceleration in first 15 min . Distance between two cities Average speed of journey
Solution:
Each horizontal block is 1/8 hr = 7.5 min
Each vertical block is 10 km/hr
Time Velocity km/hr
0 Min ( 0 hr) 0
15 Min (1/4 hr) 50
45 Min (3/4 hr) 50
60 MIn ( 1 hr) 100
90 Min ( 3/2 hr) 100
120 Min ( 2hr) 0
Acceleration in first 15 min (1/4 hr) = (50 - 0)/(1/4 - 0) = 50/(1/4)
= 200 km/h²
Distance between two cities
= (1/2)(0 + 50)(1/4 - 0) + 50 * (3/4 - 1/4) + (1/2)(50 + 100)(1 - 3/4) + 100 * (3/2 - 1) + (1/2)(100 + 0)(2 - 3/2)
= 25/4 + 25 + 75/4 + 50 + 25
= 125
Distance between two cities = 125 km
Average Speed of journey = 125/2 = 62.5 km/hr
Acceleration in first 15 min = 200 km/h²
Distance between two cities = 125 km
Average Speed of journey = 62.5 km/hr
Hope this helps..
Answer:
The series 1/5, 2/15, 4/45, 8/135... converges and sums up to 3/5
Step-by-step explanation:
Consider the infinite geometric series
1/5, 2/15, 4/45, 8/135...
With first term, a=1/5
common ratio, r = ⅔
The series converge because the common ratio, |r|<1.
The sum to infinity of a geometric series, S= a/(1-r)
S= 1/5 ÷ (1-⅔) = 1/5 ÷ 1/3 = 3/5
Therefore, the geometric series 1/5, 2/15, 4/45, 8/135... sums up to 3/5.