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sineoko [7]
3 years ago
6

Because weightlessness in outer space causes astronauts to lose bone mass, at the end of each month, an astronaut has two percen

t less bone mass than at the beginning of that month. If Lori has a 6-month mission on the International Space Station, what percentage of her bone mass will remain when she returns to Earth
Mathematics
1 answer:
vlabodo [156]3 years ago
7 0

Answer:

There will be 88.6% of her bone mass remaining when she returns to earth.

Step-by-step explanation:

According to the problem, the astronaut will have 2% less bone mass than at the beginning of that month. So let's say B_{0} is her original bone mass. In that case, her bone mass after the first month will be:

B_{1}=B_{0}(0.98)

on the second month, her bone mass will be:

B_{2}=B_{1}(0.98)=B_{0}(0.98)(0.98)=B_{0}(0.98)^{2}

on the third month, her bone mass will be:

B_{3}=B_{2}(0.98)=B_{0}(0.98)(0.98)(098)=B_{0}(0.98)^{3}

and so on, we can see a pattern here. The formula for her remaining bone mass can be generally written like this:

B_{n}=B_{0}(0.98)^{n}

where n is the number of months, so after 6 months, her remaining bone mass will be:

B_{6}=B_{0}(0.98)^{6}=0.886B_{0}

that 0.886 gives us the percentage as a decimal number. When turned into a percentage we get that:

There will be 88.6% of her bone mass remaining after 6 months.

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Sunny_sXe [5.5K]
The measured data is
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Calculate the deviations from the mean.
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Calculate the absolute deviation from the mean.
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3 years ago
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blagie [28]

Answer:

43°

Step-by-step explanation:

(x + 53)° + (x + 74)° + 73° = 180°

(x + 53 + x + 74)° = 180° - 73°

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2x = 107 - 127

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x = - 20/2

x = - 10

m\angle A = (x +53)\degree \\\\m\angle A = (-10 +53)\degree \\\\m\angle A = 43\degree \\\\

4 0
3 years ago
(Will give brainliest) Is my answer correct?? If not please correct me
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Hey!

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Answer:

(-6, 2) and (-7, -1) and (0, 0)

-------------------------------------------------

Explanation:

You reflected the triangle. You needed to translate the triangle.

y + 6 is to move up 6 units along the y-axis.

x - 5 is to move left 5 units along the x-axis.

Another thing, the question doesn't state was transformation to use so we are going to assume we are translating.

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5 0
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Which equation can be used to represent six added to twice the sum of a numbee and four is equal to one half of the difference o
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Answer:  6 + 2 (x+4) =   \frac{3}{2}(3-x)

Step-by-step explanation:

let the number be x , then :

six added to twice the sum of a number and four means :

6 + 2 (x+4)

one half of the difference of three and the number means :

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combining the two , we have

6 + 2 (x+4) = \frac{3}{2}(3-x)

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3 years ago
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