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sineoko [7]
3 years ago
6

Because weightlessness in outer space causes astronauts to lose bone mass, at the end of each month, an astronaut has two percen

t less bone mass than at the beginning of that month. If Lori has a 6-month mission on the International Space Station, what percentage of her bone mass will remain when she returns to Earth
Mathematics
1 answer:
vlabodo [156]3 years ago
7 0

Answer:

There will be 88.6% of her bone mass remaining when she returns to earth.

Step-by-step explanation:

According to the problem, the astronaut will have 2% less bone mass than at the beginning of that month. So let's say B_{0} is her original bone mass. In that case, her bone mass after the first month will be:

B_{1}=B_{0}(0.98)

on the second month, her bone mass will be:

B_{2}=B_{1}(0.98)=B_{0}(0.98)(0.98)=B_{0}(0.98)^{2}

on the third month, her bone mass will be:

B_{3}=B_{2}(0.98)=B_{0}(0.98)(0.98)(098)=B_{0}(0.98)^{3}

and so on, we can see a pattern here. The formula for her remaining bone mass can be generally written like this:

B_{n}=B_{0}(0.98)^{n}

where n is the number of months, so after 6 months, her remaining bone mass will be:

B_{6}=B_{0}(0.98)^{6}=0.886B_{0}

that 0.886 gives us the percentage as a decimal number. When turned into a percentage we get that:

There will be 88.6% of her bone mass remaining after 6 months.

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Algebraic models grade 12 math college please write the answers without explaining thank you.
Zinaida [17]

From the problem :

6^4\times6^{-5}

In multiplying expressions with the same bases, the exponent will be added accordingly.

For example :

a^m\times a^n=a^{m+n}

the exponent of a are m and n, and the product will be a raised to the sum of m and n.

Applying this to the problem, we have :

6^4\times6^{-5}=6^{4-5}=6^{-1}

The answer is d. 6^-1

6 0
1 year ago
Plz help
Yuliya22 [10]

Answer:

Solution: x = 2, y = -1 or (2, -1)

Step-by-step explanation:

Equation 1:  2x + y = 3

Equation 2: 5x - 2y = 12

Using the substitution method:

Transform the Equation 1 into its slope-intercept form:

2x + y = 3

2x - 2x + y = -2x + 3

y = 2x + 3

Substitute the value of y = -2x + 3 into Equation 2:

5x - 2y = 12

5x - 2(-2x + 3) = 12

5x + 4x - 6 = 12

9x - 6 = 12

9x - 6 + 6 = 12 + 6

9x = 18

9x/9 = 18/9

x = 2

Substitute the value of x = 2 into Equation 2 to solve for y:

5x - 2y = 12

5(2) - 2y = 12

10 - 2y = 12

10 - 10 - 2y = 12 - 10

-2y = 2

-2y/-2 = 2/-2

y = -1

Double-check whether the values for x and y will provide a true statement for both equations:

Equation 1:  2x + y = 3

2(2) + (-1) = 3

4 - 1 = 3

3 = 3 (True statement)

Equation 2: 5x - 2y = 12

5(2) - 2(-1) = 12

10 + 2 = 12

12 = 12 (True statement)

Therefore, the correct answers are: x = 2; y = -1 or (2, -1).

4 0
3 years ago
(-3+-2^2) + -(4*2) / 2
ozzi

Answer:

-3

Step-by-step explanation:

2^2 = 4

4 + (-3) = 1

4*2 = 8

8 * -1 = -8

-8 / 2 = -4

1 + -4 = -3

5 0
3 years ago
PLEASE HELP ASAP!! (NO LINKS)
Keith_Richards [23]
No it isn’t. it works for the first equation but not the second
7 0
2 years ago
I need help :(( I need to divide then put it in simplest form
ValentinkaMS [17]

2*3/8

whenever dividing the second fraction flips

2*3/8

You can divide by 2 for 2 and 8

2/2=1

8/2=4

1/4*3

=3/4

Answer is 3/4

7 0
3 years ago
Read 2 more answers
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