Answer:
100%
Explanation:
A pea plant homozygous for the trait of smooth seeds;
let that be = ss
A pea plant that is homozygous for the trait of wrinkled seeds;
let that be = ww
if ss crosses with ww; the F1 produces seeds that are all smooth
i.e ss × ww = (sw, sw, sw, sw)
From the question, we are to find the percentage of the second generation that will produce smooth seeds after self fertilization occurs.
i.e sw, sw, sw, sw × sw, sw, sw, sw
= the result will yield ssww for all F2 progeny
∴ the percentage of plants that will have smooth seeds when the F1 generation is self-fertiized is 100%
