Write in slop intercept form

Mathematics

1 answer:

Mnenie [13.5K]3 years ago

3 0

The slope intercept form is Y=-2/3x-5

You might be interested in

Fill in the blank

Marina86 [1]

Answer:

2/66 is ur answer

Step-by-step explanation:

because it will give u ur answer

6 0

2 years ago

HELP What is the area of this figure?

Mademuasel [1]

The correct answer is: [B]: "40 yd² " .
_____________________________________________________
First, find the area of the triangle:

The formula of the area of a triangle, "A":

A = (1/2) * b * h ;

in which: " A = area (in units 'squared') ; in our case, " yd² " ;

" b = base length" = 6 yd.

" h = perpendicular height" = "(4 yd + 4 yd)" = 8 yd.
___________________________________________________
→ A = (1/2) * b * h = (1/2) * (6 yd) * (8 yd) = (1/2) * (6) * (8) * (yd²) ;

= " 24 yd² " .
___________________________________________________
Now, find the area, "A", of the square:

The formula for the area, "A" of a square:

A = s² ;

in which: "A = area (in "units squared") ; in our case, " yd² " ;

"s = side length (since a 'square' has all FOUR (4) equal side lengths);

A = s² = (4 yd)² = 4² * yd² = "16 yd² "
_________________________________________________
Now, we add the areas of BOTH the triangle AND the square:
_________________________________________________
→ " 24 yd² + 16 yd² " ;

to get: " 40 yd² " ; which is: Answer choice: [B]: " 40 yd² " .
_________________________________________________

4 0

3 years ago

Sally has seventy dollars to spend on eight books. After buying them she had thirteen dollars. How much did each book cost?

Anit [1.1K]

Answer:

7.13 each

Step-by-step explanation:

70 - 13 = 57. Divide 57/8 and get your answer

(7.125 rounded is 7.13)

5 0

3 years ago

Read 2 more answers

1+secA/sec A = sin^2 A / 1-cos A

Fofino [41]

Answer: see proof below

<u>Step-by-step explanation:</u>

$\dfrac{1+\sec A}{\sec A}=\dfrac{\sin^2 A}{1-\cos A}$

Use the following Identities:

sec Ф = 1/cos Ф

cos² Ф + sin² Ф = 1

<u>Proof LHS → RHS</u>

$\text{LHS:}\qquad \qquad \dfrac{1+\sec A}{\sec A}$

$\text{Identity:}\qquad \qquad \dfrac{1+\frac{1}{\cos A}}{\frac{1}{\cos A}}$

$\text{Simplify:}\qquad \qquad \dfrac{\frac{\cos A+1}{\cos A}}{\frac{1}{\cos A}}\\\\\\.\qquad \qquad \qquad =\dfrac{1+\cos A}{1}$

$\text{Multiply:}\qquad \qquad \dfrac{1+\cos A}{1}\cdot \bigg(\dfrac{1-\cos A}{1-\cos A}\bigg)\\\\\\.\qquad \qquad \qquad =\dfrac{1-\cos^2 A}{1-\cos A}$