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OLga [1]
3 years ago
8

In the graph, the vector terminating at A represents the complex number z. The vector terminating at B represents the product of

z and -2. Which graph correctly represents the product?

Mathematics
2 answers:
marin [14]3 years ago
6 0

Answer:


Step-by-step explanation:

A = z

B = -2z


Since  z is in the second quadrant ( x is negative and y is positive)

when we multiply by -2,   B is   (-*-  = +,  + * - = -)

B is in the 4th quadrant ( x is positive, y is negative)


This is the only graph that meets that requirement.

Oksi-84 [34.3K]3 years ago
6 0

Answer:

The answer is the second graph

Step-by-step explanation:

1. A complex number is coumposed by a real coordinate (in the x axis) and a imaginary coordinate (in the Y axis). If we see the vector A, we can note its direction is <-1,3>  .

2. When we multiply a number by a vector, we multiply the number by each component of the vector, as follows:

       -2  *   <-1,3>  =  <2,-6>

We can note the new direction <2,-6> is represented by the second graph.

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olchik [2.2K]

Option A: \frac{1}{3} is the dilation factor

Explanation:

The Coordinates of the square ABCD are A(-21,18), B(-12,18), C(-12,9), D(-21,9)

Also, the coordinates of the square A'B'C'D' are A'(–7, 6), B'(-4,6), C'(-4,3), D'(-8,3)

Now, we shall determine the scale factor in the dilation if the coordinates A' and C'.

Since, the dilation is the enlargement of the image in the same shape but different size.

To determine the scale factor, let us divide A'C' by AC

Thus, we have,

\begin{aligned}A^{\prime} C^{\prime} &=\sqrt{(-4+7)^{2}+(3-6)^{2}} \\&=\sqrt{3^{2}+(-3)^{2}} \\&=\sqrt{9+9} \\&=\sqrt{18}\\&=3\sqrt{2} \end{aligned}

Also,

\begin{aligned}A C &=\sqrt{(-12+21)^{2}+(9-18)^{2}} \\&=\sqrt{9^{2}+(-9)^{2}} \\&=\sqrt{81+81} \\&=\sqrt{162}\\&=9\sqrt{2} \end{aligned}

Dividing A'C' by AC, we have,

\frac{A'C'}{AC} =\frac{3\sqrt{2} }{9\sqrt{2}} =\frac{1}{3}

Thus, \frac{1}{3} is the dilation factor

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