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Artyom0805 [142]
4 years ago
12

When Lily does a self-inventory, she lists her knowledge of Excel, her proficiency in bookkeeping, and her training in customer

service. These go under the category of:
A. goals.
B. abilities.
C. attributes.
Mathematics
1 answer:
Anika [276]4 years ago
6 0

Answer:

The above mentioned qualities go under the category of abilities.

Step-by-step explanation:

Lily does a self-inventory to find out theat she has knowledge of Excel , proficiency in bookkeeping and training in customer service .

Ability is used to refer a person's native aptitude in a specific field.

Ability can also be trained and honed and can be made better with practice.

All of Lily's qualities mentioned come under the same above mentioned specifications. All her talents can be trained and can be bettered.

Hence her qualities come under the category of abilities.

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Which would be appropriate compatible numbers to use to estimate (19 4/5) (4/6) A. 16(1/3) B. 19(2/3) C. 20(1/2) D. 20(1)
podryga [215]

Answer:

C. 20(1/2)

Step-by-step explanation:

Let's find the value of the expression before looking for the nearest estimate

(19 4/5) (4/6) = 19 *(4/5)(4/6)

(19 4/5) (4/6) = 19(16/30)

(19 4/5) (4/6) = 19(8/15)

(19 4/5) (4/6) = (19*8)/15

(19 4/5) (4/6) = 152/15

(19 4/5) (4/6) = 10(2/15)

A. 16(1/3) =5.33

B. 19(2/3) = 12.667

C. 20(1/2) = 10

D. 20(1)= 20

The nearest to the expression is C. 20(1/2)

6 0
3 years ago
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Anna007 [38]

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6 0
3 years ago
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If a total amount is 5 7/8 and 6 people need to be fed, how much is a serving size?
PolarNik [594]

<em>Answer:</em>

47/48

<em>Explanation:</em>

Since 5 7/8 is so close to 6, it is easier to work this problem by considering the difference.

The serving size is 1/6 of the total amount, so you want to find ...

... (5 7/8) × (1/6)

Following the observation above, we can compute it as ...

... (6 - 1/8) × (1/6) = (6/6) - (1/8)×(1/6)

... = 1 - 1/48

... = <em>47/48</em>

5 0
3 years ago
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tatyana61 [14]
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8 0
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PilotLPTM [1.2K]
5sqrt(x+7)=-10
Dividing both sides by 5:
5sqrt(x+7)/5=-10/5
sqrt(x+7)=-2
Squaring both sides of the equation:
[sqrt(x+7)]^2=(-2)^2
x+7=4
x+7-7=4-7
x=-3

Replacing in the original equation:
5sqrt(x+7)=-10
5sqrt(-3+7)=-10
5sqrt(4)=-10
5(2)=-10
10=-10 It's not equal, then x=-3 is an extraneous solution
7 0
3 years ago
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