Cost per meter(C) = $60/m
Length of rectangular field(L) = 50m
L = 2W
-> W = L/2
-> W = 50/2
-> Width of rectangular field = 25m
Cost of one field length(l) = L x C
-> l = 50 x 60
-> l = $3000
Two of the lengths of the field = 2 x l
-> 2 x $3000
-> $6000
Cost of one field width(w) = W x C
-> w = 25 x 60
-> w = $1500
Two of the widths of the field = 2 x w
-> 2 x $1500
-> $3000
Cost of fencing entire field = $6000+$3000
Hence, total field cost = $9000
Plug in numbers. if originally, it was V=1/2 * 1 * 1 * 2=1
<span>tripling the dimensions would be V=1/2 * 3 * 3 * 6=27 </span>
<span>it would be 27 times larger. this could also be found by 3^3, just as doubling would render 2^3
</span>
P = A / (1 + rt)
P = 80000 / (1 + (0.09)(0.5))
P = <span>$ 76,555.02</span>
Draw the diameter from point (-1, -5) to point (2, 3).
The triangle has base 3 and height 8.
The diameter of the semicircle is the hypotenuse of the triangle.


The radius is half the diameter.

The total area is the area of the triangle plus the area of the semicircle.


The volume at time <span>t = 25 seconds
since </span><span> V = 4 sqrt(t) cm3,
V(5)= 4*</span><span>sqrt(25)cm^3=4*5=20cm^3</span>